In theory, lead should react with dilute sulfuric acid, to give lead(II) sulfate and hydrogen. In practice the reaction is very slow, because lead sulfate is insoluble in water and quickly clogs up the lead surface, and because lead is relatively unreactive.
When lead(II) nitrate (Pb(NO3)2) and sulfuric acid (H2SO4) react, lead(II) sulfate (PbSO4) and nitric acid (HNO3) are produced. This reaction is a double displacement reaction where the ions in the reactants switch partners to form the products. Lead(II) sulfate is an insoluble salt that precipitates out of solution.
The chemical symbol for dilute sulfuric acid is H2SO4.
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To balance the chemical equation Pb + PbO2 + H2SO4 → H2O + PbSO4, start by balancing the Pb atoms on the left side by adding a coefficient of 2 in front of Pb on the left side. Then balance the SO4 atoms by adding a coefficient of 4 in front of H2SO4. The balanced equation is 2Pb + PbO2 + 4H2SO4 → 2H2O + 2PbSO4.
Sulfphuric acid is the British spelling. The American spelling is sulfuric acid. Anyways, the formula is H2SO4.
Reactions of Lead (Pb) with cold, dilute acids are very slow. Some examples are as follows:- 1) Reaction with dil. HCl and gives PbCl2 and H2 gas. Pb + 2HCl ---> PbCl2 + H2 Solid Aqs. Aqs. Gas 2) Reaction with dil. H2SO4 and gives PbSO4 and H2 gas. Pb + H2SO4 ----> PbSO4 + H2 Solid Aqs. Aqs. Gas 3) Reaction with dil. HNO3 and gives Pb(NO3)2 and H2 gas. Pb + 2HNO3 ------> Pb(NO3)2 + H2 Solid Aqs. Aqs. Gas Regards- Ashutosh talktomehiya@gmail.com
When lead(II) nitrate (Pb(NO3)2) and sulfuric acid (H2SO4) react, lead(II) sulfate (PbSO4) and nitric acid (HNO3) are produced. This reaction is a double displacement reaction where the ions in the reactants switch partners to form the products. Lead(II) sulfate is an insoluble salt that precipitates out of solution.
The chemical symbol for dilute sulfuric acid is H2SO4.
H2SO4(dilute)
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To balance the chemical equation Pb + PbO2 + H2SO4 → H2O + PbSO4, start by balancing the Pb atoms on the left side by adding a coefficient of 2 in front of Pb on the left side. Then balance the SO4 atoms by adding a coefficient of 4 in front of H2SO4. The balanced equation is 2Pb + PbO2 + 4H2SO4 → 2H2O + 2PbSO4.
Sulfphuric acid is the British spelling. The American spelling is sulfuric acid. Anyways, the formula is H2SO4.
For lead (II) nitrate: H2SO4 + Pb(NO3)2 -----> 2HNO3 + PbSO4 ...................................................(white)
Na2CO3 + H2SO4 -> Na2SO4 + CO2 + H2O
Should be, assuming ideal reaction....... Pb + H2SO4 --> PbSO4 + H2 Products are lead sulfate and hydrogen gas.
When sodium hydrogen carbonate reacts with dilute sulfuric acid (H2SO4), carbon dioxide gas, water, and sodium sulfate are produced. This reaction is represented by the following chemical equation: NaHCO3 + H2SO4 → CO2 + H2O + Na2SO4