Yes, SO4 2- can be drawn without violating the octet rule. It is also a resonance structure. Here's an illustration below (ignore the dots, it was the only way it posted correctly!):
.......O
.......|
O -- S -- O
.......
.......O
Hope this helped!
2
Yes, in the Lewis structure of BH3, the boron atom does not follow the octet rule as it only has 6 electrons around it (2 electrons from each B-H bond). Boron is an exception to the octet rule and can form stable compounds with incomplete octets.
The bolded statements are true:1. The octet rule can be violated. 2. Atoms are most stable when their atomic number is divisible by 8.3. All free atoms contribute eight valence electrons to form molecules.4. Only the oxygen atom can have an expandable octet.5. In order to obey the octet rule, some atoms have to share more than one pair of electrons.
Calcium is a group 2 element and typically loses 2 electrons to achieve a stable electron configuration with a full outer shell. By losing these 2 electrons, calcium is able to achieve an octet configuration in its outermost shell, similar to the noble gas configuration.
more than sure that whole group is covalent bonding such as Iodine is written I2 or Bromine is Br2. Fluorine is also in this, example F2, the 2 outer electrons as each is 19, 2,8,8,1 is shared between the 2 atoms.
Hydrogen is the atom that doesn't always obey the octet rule. It only needs 2 electrons to have a full outer shell, rather than the 8 electrons typically required by the octet rule. Oxygen and bromine usually follow the octet rule.
PF5 obeys the octet rule as it has 5 bonding pairs of electrons around the central phosphorus atom, satisfying the octet. Cs2 does not follow the octet rule as Cs is in Group 1 and can only form ionic bonds. BBr3 is an exception to the octet rule as boron has only 6 electrons around it due to the empty d orbital. CO3 2- also obeys the octet rule as each oxygen atom has a complete octet.
No. Hydrogen needs only 2 electrons for a full outer shell rather than the usual 8.
2
Yes, in the Lewis structure of BH3, the boron atom does not follow the octet rule as it only has 6 electrons around it (2 electrons from each B-H bond). Boron is an exception to the octet rule and can form stable compounds with incomplete octets.
Neon does not typically form ionic compounds because it already has a full valence shell with 8 electrons, satisfying the octet rule. Its electron configuration (1s^2 2s^2 2p^6) makes it very stable and unreactive with other elements.
The bolded statements are true:1. The octet rule can be violated. 2. Atoms are most stable when their atomic number is divisible by 8.3. All free atoms contribute eight valence electrons to form molecules.4. Only the oxygen atom can have an expandable octet.5. In order to obey the octet rule, some atoms have to share more than one pair of electrons.
Calcium is a group 2 element and typically loses 2 electrons to achieve a stable electron configuration with a full outer shell. By losing these 2 electrons, calcium is able to achieve an octet configuration in its outermost shell, similar to the noble gas configuration.
Some elements that are known to violate the octet rule are: Hydrogen, Helium and Lithium (two electrons) Aluminum and Boron (less than octet but will form an octet if possible), Period 3 elements with p orbitals (more than an octet using empty d orbitals), noble gas compounds (more than an octet), and elements like nitrogen with an odd number of electrons (form free radicals when octets are not possible).
Beryllium (Be) is an element in group 2 of the periodic table. It has 2 energy levels and 2 valence electrons in the outermost energy level. It reacts by losing 2 electrons to attain a noble gas structure.
more than sure that whole group is covalent bonding such as Iodine is written I2 or Bromine is Br2. Fluorine is also in this, example F2, the 2 outer electrons as each is 19, 2,8,8,1 is shared between the 2 atoms.
Group 18 elements obey octet rule. They have 8 valence electrons (except for helium, which has 2 valence electrons) and are stable. Thus they are chemically inert under normal conditions.