H3PO4 + 3NaOH --------> Na3PO4 + 3H2O
The balanced chemical equation for the reaction is: 3 H3PO4 + 2 NaOH -> Na3PO4 + 3 H2O From the equation, we can see that 3 moles of H3PO4 react with 2 moles of NaOH. Calculate the molar mass of H3PO4 and NaOH. Then, use the molar ratio from the balanced equation to calculate the amount of H3PO4 needed to react with 25.4g of NaOH.
To balance the reaction between H3PO4 and NaOH, first write out the chemical equation: H3PO4 + 3 NaOH -> Na3PO4 + 3 H2O Now, each element must have the same number of atoms on both sides of the equation for it to be balanced. Adjust the coefficients in front of each compound to achieve this balance.
Usually these reaction are done with a substantial excess of NaOH. You would getH3PO4 + 3NaOH --> Na3PO4(aq) + 3HOH.
KHC8H4O4(aq) + NaOH(aq) → KNaC8H4O4(aq) + H2O(l) NaOH(aq) + KHP(aq) => Na+ + KP- + H2O(l)
3NaOH + H3PO4 -> Na3PO4 +3H2O The usual salt, sodium phosphate, and water.
H3PO4 + NaOH ----> Na2HPO4 + H2O
The balanced chemical equation for the reaction is: 3 H3PO4 + 2 NaOH -> Na3PO4 + 3 H2O From the equation, we can see that 3 moles of H3PO4 react with 2 moles of NaOH. Calculate the molar mass of H3PO4 and NaOH. Then, use the molar ratio from the balanced equation to calculate the amount of H3PO4 needed to react with 25.4g of NaOH.
Na3PO4+H2O->NaOH+H3PO4 just balance it.
To balance the reaction between H3PO4 and NaOH, first write out the chemical equation: H3PO4 + 3 NaOH -> Na3PO4 + 3 H2O Now, each element must have the same number of atoms on both sides of the equation for it to be balanced. Adjust the coefficients in front of each compound to achieve this balance.
One possible reaction is 2 NaOH + H3PO4 = Na2HPO4 + 2 H2O.
Usually these reaction are done with a substantial excess of NaOH. You would getH3PO4 + 3NaOH --> Na3PO4(aq) + 3HOH.
KHC8H4O4(aq) + NaOH(aq) → KNaC8H4O4(aq) + H2O(l) NaOH(aq) + KHP(aq) => Na+ + KP- + H2O(l)
my balance sheet does not balance why?
Balanced equation:12 HClO4 + P4O10 = 4 H3PO4 + 6 Cl2O7
3NaOH + H3PO4 -> Na3PO4 +3H2O The usual salt, sodium phosphate, and water.
During the titration of H3PO4 with NaOH to determine the equivalence point, a known volume of H3PO4 is gradually added to a solution of NaOH until the reaction reaches a neutral point. This is detected using an indicator that changes color at the equivalence point. The volume of NaOH required to reach this point is used to calculate the concentration of H3PO4.
K3PO4 + 3HCl -> 3KCl + H3PO4 Since K on the reactant side has 3 potassium atoms, K on the product side should also have 3 potassium atoms to balance the equation. Since you put the 3 on KCl of the product side, another 3 has to go on the Cl on the reactant side which also matches the 3 hydrogen atoms on the product side in H3PO4. If you check, the equation is now balanced. Everything that appears on the left, equally appears on the right