study
If the temperature remains constant, the volume of the gas will halve when the pressure doubles. This is described by Boyle's Law, which states that pressure and volume are inversely proportional when temperature is held constant.
When the volume of a confined gas is reduced by half at a constant temperature, the pressure of the gas will double according to Boyle's Law. This is because the product of pressure and volume is constant for a given amount of gas at constant temperature. When the volume decreases, the pressure increases to maintain this equilibrium.
The initial pressure is halved. Use Boyle's law that relates pressure & volume at a constant temperature. P1V1 = P2V2 In this case the V1(initial volume) is doubled so V2 = 2V1 P2 = P1V1/V2 = P1V1/2V1 P2 = (1/2)*P1
If the volume of a container of air is reduced, the pressure of the air inside the container will increase. This is because the volume and pressure of a gas are inversely proportional according to Boyle's Law. The particles inside the container will collide more frequently with the walls, leading to an increase in pressure.
The volume is halved (Explanation): this is boyle's law PV=PV. In order to keep this equation true, if one variable (pressure in this case) is doubled, the other variable must be the reciprocal of that (in this case 1/2, which is reciprocal of double).
If the temperature remains constant, the volume of the gas will halve when the pressure doubles. This is described by Boyle's Law, which states that pressure and volume are inversely proportional when temperature is held constant.
The pressure drops.
60
When the volume of a confined gas is reduced by half at a constant temperature, the pressure of the gas will double according to Boyle's Law. This is because the product of pressure and volume is constant for a given amount of gas at constant temperature. When the volume decreases, the pressure increases to maintain this equilibrium.
The initial pressure is halved. Use Boyle's law that relates pressure & volume at a constant temperature. P1V1 = P2V2 In this case the V1(initial volume) is doubled so V2 = 2V1 P2 = P1V1/V2 = P1V1/2V1 P2 = (1/2)*P1
If the volume of a gas doubles at constant temperature, the pressure of the gas decreases by half according to Boyle's Law. This is because pressure is inversely proportional to volume in a closed system at constant temperature.
If the volume of a container of air is reduced, the pressure of the air inside the container will increase. This is because the volume and pressure of a gas are inversely proportional according to Boyle's Law. The particles inside the container will collide more frequently with the walls, leading to an increase in pressure.
The volume is halved (Explanation): this is boyle's law PV=PV. In order to keep this equation true, if one variable (pressure in this case) is doubled, the other variable must be the reciprocal of that (in this case 1/2, which is reciprocal of double).
Are you stating or asking ? If that's a statement, then it's an incorrect one. At constant temperature, the product of (pressure) x (volume) is constant. So, if the volume changed by a factor of 3, the pressure must also change by a factor of 3 ... the pressure must triple.
Are you stating or asking ? If that's a statement, then it's an incorrect one. At constant temperature, the product of (pressure) x (volume) is constant. So, if the volume changed by a factor of 3, the pressure must also change by a factor of 3 ... the pressure must triple.
In a perfectly flexible and expandable container (pressure is constant) the volume of an ideal gas will double as the absolute temperature doubles. For a non-ideal gas and non-perfect container, your results will vary but will always be somewhat less than double.
In a perfectly flexible and expandable container (pressure is constant) the volume of an ideal gas will double as the absolute temperature doubles. For a non-ideal gas and non-perfect container, your results will vary but will always be somewhat less than double.