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What is the concentratuon of a hcl solution if 25.0 ml is required to neutralize 38.5 ml of a 0.500m solution of naoh?
To find the concentration of HCl, you can use the formula: moles of NaOH = moles of HCl. From the given information, you can calculate the moles of NaOH used to neutralize the acid. Then, use the volume and concentration of NaOH to determine the concentration of HCl.
What volume of NaOH was used in the titration?
To determine the volume of NaOH used in the titration, you need to know the concentration of the NaOH solution and the volume required to reach the endpoint. Use the formula: volume NaOH (L) = volume HCl (L) * concentration HCl / concentration NaOH.
Balanced equation for HCl and NaOH?
1 HCl + 1 NaOH ---> 1 NaCl + 1 H(OH)
What volume in mL of a 1.06 M NaOH solution is required to neutralize 11 g of HCl?
Balanced equation. NaOH + HCl -> NaCl + H2O all one to one. find moles HCl. 11 grams HCl (1 mole HCl/36.458 grams ) = 0.3017 moles HCl Moles HCl same as moles NaOH Molarity = moles of solute/Liters of solution 1.06 M NaOH = 0.3017 moles NaOH/liters of solution = 0.2846 Liters this is equal to..... 285 milliliters of NaOH needed
Identify the reactants in the reaction HCl plus NaOH NaCl plus H2O?
The reactants are hydrochloric acid (HCl) and sodium hydroxide (NaOH).
What is the concentratuon of a hcl solution if 25.0 ml is required to neutralize 38.5 ml of a 0.500m solution of naoh?
To find the concentration of HCl, you can use the formula: moles of NaOH = moles of HCl. From the given information, you can calculate the moles of NaOH used to neutralize the acid. Then, use the volume and concentration of NaOH to determine the concentration of HCl.
What is chemical formula for sodium chlorinde?
NaCl In water this dissociates to NaOH+ & HCl-
What is the chemical formula of saltwater?
Na1+ Cl1- + H+1 OH1- = NaOH + HCl
What volume of NaOH was used in the titration?
To determine the volume of NaOH used in the titration, you need to know the concentration of the NaOH solution and the volume required to reach the endpoint. Use the formula: volume NaOH (L) = volume HCl (L) * concentration HCl / concentration NaOH.
Balanced equation for HCl and NaOH?
1 HCl + 1 NaOH ---> 1 NaCl + 1 H(OH)
What volume in mL of a 1.06 M NaOH solution is required to neutralize 11 g of HCl?
Balanced equation. NaOH + HCl -> NaCl + H2O all one to one. find moles HCl. 11 grams HCl (1 mole HCl/36.458 grams ) = 0.3017 moles HCl Moles HCl same as moles NaOH Molarity = moles of solute/Liters of solution 1.06 M NaOH = 0.3017 moles NaOH/liters of solution = 0.2846 Liters this is equal to..... 285 milliliters of NaOH needed
Identify the reactants in the reaction HCl plus NaOH NaCl plus H2O?
The reactants are hydrochloric acid (HCl) and sodium hydroxide (NaOH).
Is HC1 the formula for sodium hydroxide?
No, its NaOH HCl (L not 1) is the designation for hydrochloric acid, the 3rd strongest acid.
A 25.0 ml sample of hcl was titrated to the endpoint with 15.0 ml of 2.0 normality naoh what was the normality of th hcl what was its molarity?
The normality of HCl can be calculated using the equation: Normality (HCl) * Volume (HCl) = Normality (NaOH) * Volume (NaOH). Solving for the normality of HCl gives 6.0N. The molarity of the HCl solution can be calculated using the formula: Molarity = Normality / n-factor. Assuming the n-factor for HCl is 1, the molarity of the HCl solution would be 6.0 M.
How would you know the Normality of HCL?
To determine the normality of HCl (hydrochloric acid), you can perform a titration experiment with a standardized solution of sodium hydroxide (NaOH) of known concentration. By recording the volume of NaOH required to neutralize the HCl, you can calculate the normality of the acid using the formula: Normality = (Molarity of NaOH) x (Volume of NaOH used) / Volume of HCl sample.
How many milliliters of 0.400 M NaOH are required to completely neutralize 20.00 mL of 0.200 M HCl?
To neutralize HCl with NaOH, the mole ratio is 1:1. So, the moles of HCl are 0.200 M x 0.020 L = 0.004 moles. Since NaOH and HCl react in a 1:1 ratio, we need 0.004 moles of NaOH. Using the molarity formula, we find that we need 0.010 L or 10.00 mL of 0.400 M NaOH.
What is the formula equation for hydrochloric acid sodium hydroxide-sodium chloride water?
This equation is HCl (aq) + NaOH (aq) -> NaCl (aq) + H2O.
