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Its atomic number is 13. Hence 13 electrons. 2 in the K shell, 8 in the L shell and 3 will be in the M shell. Hence these three free electrons would make the aluminum trivalent.

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12y ago
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11y ago

1s2 2s2 2p6 3s2 3p1

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14y ago

1s2 2s2 2p6 3s2 3p1

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11y ago

1s2, 2s2,2p6

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15y ago

2-8

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Q: Give the electron configuration for an aluminum ion Al3?
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