Its atomic number is 13. Hence 13 electrons. 2 in the K shell, 8 in the L shell and 3 will be in the M shell. Hence these three free electrons would make the aluminum trivalent.
1s2 2s2 2p6 3s2 3p1
1s2 2s2 2p6 3s2 3p1
1s2, 2s2,2p6
2-8
When aluminum (Al, #13) reacts, it loses its three valence electrons to achieve the same electron configuration as neon (Ne, #10.) That configuration is 1s22s22p6. So yes, Al+3 has the same configuration as neon.
N3- , O2- , F- , Na+ , Mg2+ , Al3+ all have the same electron configuration as Neon.
+3
An isotope of Magnesium, specifically Mg26.
The formula for aluminum oxide is Al2O3: Molar mass =581.77g/mol Al2O3.In one mole Al2O3, there are two moles of Al3+ ions, therefore 2 moles Al3+ x 26.982g/mol Al3+ = 53.964g Al3+ in one mole of Al2O3.GIVEN: mass of Al3+ = 53.964 g Al3+;Molar mass of Al2O3 = 581.77 g Al2O3UNKNOWN: % Al3+EQUATION:% Al3+...=...g Al3+x 100...g Al2O3% Al3+...=...53.964g Al3+x100......=...9.2758% Al3+581.77g Al2O3
Al3+
Al3+
Al3+
Here is the equation - Al3+ + 3e- -> Al
When aluminum (Al, #13) reacts, it loses its three valence electrons to achieve the same electron configuration as neon (Ne, #10.) That configuration is 1s22s22p6. So yes, Al+3 has the same configuration as neon.
N3- , O2- , F- , Na+ , Mg2+ , Al3+ all have the same electron configuration as Neon.
Aluminum (Al) follows the configuration of the noble gas before it, neon (Ne). Aluminum has 3 electrons in the 3rd level. Two of them are in the 3s subshell and the other is in the 3p subshell.[Ne]3s23p1
Aluminum has trivalent cation. It is Al3+
+3
Aluminum needs to lose 3 electrons to gain a noble gas electron configuration.
An isotope of Magnesium, specifically Mg26.
Al3 - Aluminum cationCN-Cyanide ion