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[H3O+][OH-] = Kw = 1x10^-14
[OH-] = 1x10^-14/0.0034 = 1x10^-14/3.4x10^-3
[OH-] = 2.9x10^-12 M

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Q: Given that you have a H3O concentration of 0.0034 M what is the OH-?
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How is the Kw constant developed?

it is the concentration of H3O+ times the concentration of OH-


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