I believe ground state menas in its noble gas form therefor all elements in period 2 such as nitrogen have a ground state of He
The ground state electron configuration for the element with the atomic number corresponding to the keyword "fe" is Ar 3d6 4s2.
The element with that electron configuration is Iron.
Gallium, or Ga, has an atomic number of 31. The ground state electron configuration is 1s2 2s2 2p6 3s2 3p6 4s2 3d10 4p1.
The electron configuration of atomic number 26 (iron) is 1s2 2s2 2p6 3s2 3p6 4s2 3d6.
The electron configuration of an atom with the atomic number 10 (neon) is 1s2 2s2 2p6.
The ground state electron configuration for the element with the atomic number corresponding to the keyword "fe" is Ar 3d6 4s2.
Nitrogen has 7 protons and thus 7 electrons to be neutral. It's total configuration is 1s2 2s2 2p3. Therefore, its valence configuration is 2s2 2p3.
The element with that electron configuration is Iron.
Electron configuration for an atom is the distribution of electrons on atomic orbitals.
Gallium, or Ga, has an atomic number of 31. The ground state electron configuration is 1s2 2s2 2p6 3s2 3p6 4s2 3d10 4p1.
The electron configuration of atomic number 26 (iron) is 1s2 2s2 2p6 3s2 3p6 4s2 3d6.
The element with the noble-gas configuration He 2s2 2p3 is nitrogen (N), which has an atomic number of 7. This configuration represents the electron arrangement in nitrogen, where it has two electrons in the 2s orbital and three electrons in the 2p orbital.
The noble gas configuration of nitrogen is [He] 2s^2 2p^3. This means that nitrogen has the same electron configuration as helium for the inner electrons, with 2 electrons in the 2s orbital and 3 electrons in the 2p orbital.
The electron configuration of an atom with the atomic number 10 (neon) is 1s2 2s2 2p6.
The sum of the superscript in an electron configuration is equal to the atomic number.
The sum of the superscript in an electron configuration is equal to the atomic number.
Vanadium ( V) has that configuration. Its atomic number is 23.