HCN is linear. Both atoms are 180 degrees from one another.
We know carbon has 4 valance electrons. And needs 4 bonds to complete the shell.
Nitrogen has 5 and needs 3 to complete the shell.
Hydrogen has 1 and needs 1 to complete the shell.
So we want an arrangement where all shells are filled...ideally.
We can do this with a single bond from H to C and a triple bond from N to C.
C has no lone pairs...nothing else blocking the way. So we want the other two atoms on the carbon to be as far away from each other as possible...so it's a 180 angle.
This kind of thing is only confusing because of examples like H2O that are bent...but remember the oxygen in H2O has a lone pairs that need to be repelled by other electrons...meaning lone pairs repel each other as well as other atoms and vice versa so you end up with much more difficult angles.
But in this case, it's nice and simple. Linear molecule.
When the central atom of a molecule has unshared electrons, the bond angles will be less than the ideal angles for a given molecular geometry. This is because the unshared electrons create additional repulsion, pushing the bonded atoms closer together and reducing the bond angles.
No, BCl3 does not have an idealized bond angle. The central boron atom in BCl3 has a trigonal planar molecular geometry, which leads to bond angles of approximately 120 degrees due to electron repulsion around the boron atom.
If it is non polar, the bond angles are as follows:I-P-I bond angles: 120ºBr-P-Br bond angles: 180ºI-P-Br bond angles: 90º
The molecular geometry characterized by 109.5 degree bond angles is tetrahedral. This geometry occurs when a central atom is bonded to four surrounding atoms with no lone pairs on the central atom. An example of a molecule with this geometry is methane (CH4).
I'd say it would be easier to list the ones that aren't, but in actuality it would be impossible to list either. Any molecule that has tetrahedral geometry qualifies, examples, ammonium, methane, ethane, propane...ANY alkane, any quaternary ammonium compound.
When the central atom of a molecule has unshared electrons, the bond angles will be less than the ideal angles for a given molecular geometry. This is because the unshared electrons create additional repulsion, pushing the bonded atoms closer together and reducing the bond angles.
No, BCl3 does not have an idealized bond angle. The central boron atom in BCl3 has a trigonal planar molecular geometry, which leads to bond angles of approximately 120 degrees due to electron repulsion around the boron atom.
If it is non polar, the bond angles are as follows:I-P-I bond angles: 120ºBr-P-Br bond angles: 180ºI-P-Br bond angles: 90º
The molecular geometry characterized by 109.5 degree bond angles is tetrahedral. This geometry occurs when a central atom is bonded to four surrounding atoms with no lone pairs on the central atom. An example of a molecule with this geometry is methane (CH4).
I'd say it would be easier to list the ones that aren't, but in actuality it would be impossible to list either. Any molecule that has tetrahedral geometry qualifies, examples, ammonium, methane, ethane, propane...ANY alkane, any quaternary ammonium compound.
Hybridization influences bond angles by determining the arrangement of electron domains around a central atom. Hybridization allows the orbitals to mix and form new hybrid orbitals, which can influence the geometry of the molecule and consequently affect the bond angles. For example, in a molecule with sp3 hybridization, the bond angles are approximately 109.5 degrees due to the tetrahedral arrangement of electron domains.
Trigonal planer with SP2 hybridized central atom (B)
The atoms sharing the electron pairs will spread out around the central atom.
In formaldehyde (H₂C=O), the carbon atom is sp² hybridized, resulting in a trigonal planar geometry around the carbon. The approximate bond angles in this molecule are around 120 degrees. The oxygen atom also contributes to this planar arrangement, with the hydrogen atoms positioned symmetrically around the carbon atom.
It takes up space like an "invisible" atom.
The molecular geometry of chloroform (CHI3) is tetrahedral. In this molecule, the central carbon atom is bonded to one hydrogen atom and three iodine atoms. The presence of these four bonded pairs of electrons around the carbon leads to a tetrahedral arrangement, with bond angles of approximately 109.5 degrees. However, the presence of larger iodine atoms affects the exact bond angles.
The vesper type of HCO3 is trigonal planar. This means that the three atoms around the central carbon atom are arranged in a flat, triangular shape with bond angles of approximately 120 degrees.