Compound 1 has two stereoisomers.
The stereoisomers is one of the alcohols present. The total number of alcohols is 11. This is not a high number as one who expect.
Indicate whether each of the following pairs represent constitutional isomers, the same compound, or different compounds 2-methoxybutane and 3-methyl-2-butanol
The subscript of potassium in a compound formed between potassium and sulfur would be 1, as it is understood to exist as K+ in ionic compounds.
The compound is actually called Sodium Iodide. 1 molecule of Sodium Iodide contains 1 atom of Sodium and 1 atom of Iodine. Chemical formula = NaI
There isn't one; that compound can't exist (technically, it might exist as a carbanion or carbocation or free radical, but not as a stable compound). Adding a hydrogen to the third carbon would make it 1-butanal; removing one from the second carbon would make it but-2-en-1-al.
The stereoisomers is one of the alcohols present. The total number of alcohols is 11. This is not a high number as one who expect.
The compound formed between sodium and francium would be NaFr, with sodium as the cation and francium as the anion. This compound would have a 1:1 ratio of sodium to francium ions.
Indicate whether each of the following pairs represent constitutional isomers, the same compound, or different compounds 2-methoxybutane and 3-methyl-2-butanol
The compound RuS is called ruthenium sulfide. It consists of ruthenium (Ru) and sulfur (S) and can exist in several stoichiometric forms, with RuS typically referring to a 1:1 ratio of ruthenium to sulfur. This compound is of interest in various chemical and materials science applications.
The subscript of potassium in a compound formed between potassium and sulfur would be 1, as it is understood to exist as K+ in ionic compounds.
MgBr2 is Magnesium bromide - Mg2Br2 does not exist
Many Types
One example of a metal with a negative oxidation state in its compound is iron in the compound FeH2, where iron has an oxidation state of -2. Another example is copper in the compound Cu2S, where copper has an oxidation state of -1.
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The compound is actually called Sodium Iodide. 1 molecule of Sodium Iodide contains 1 atom of Sodium and 1 atom of Iodine. Chemical formula = NaI