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u have not mentioned the unit with logical address, if its byte , u cannot have such small memory , as page size is bigger i.e 4*1024=4096bytes

Assuming it is 2000kb=2000*1024=2048000bytes

page no will be :

2048000/4096=500 its the page no, and to

calculate the offset :

2048000%4096=0;

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