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The most common way to determine the ion of an atom on the Periodic Table is to look at the group it is in. Moving from left to right the elements will usually have the ionic charges of +1,+2,+3,+-4,-3,-2,-1. All elements in each group will have the same ionic charge . The transition metals are not as easy as this but a general method to use is that most transition metals have a charge of +2. This iosnt true for all of them but if you are not sure on their charge it is bsest to go with +2. Otherwise the other method i have said is a good way to determine the ion that will form

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14y ago
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13y ago

If the periodic table used is the usual "long form" table with 18 columns numbered from left to right and the symbol of the metal of interest is in column 1 or 2, the atom will lose the same number of electrons as its column number to form its most stable cation. The largest number of electrons that the atom might lose to form a cation is usually the same as the column number for columns 3 through 7, but in practice, almost no cations with charges greater than +4 are stable. However, the metals in these columns often share the maximum number of electrons predicted by this rule to form anions with very electronegative non metals such as oxygen and fluorine. Metals in columns 13 through 15 can usually lose no more than the number corresponding to the last digit only of the column number to form cations, but again + 5 cations are rare. (Note that the atoms in columns 14 and 15 in the third period or lower are usually not metals at all.)

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Q: How can the periodic table be used to predict how many electrons a certain metal atoms loses to form an ionic compound?
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