How can you remove iron components from acid sulfuric?

Answer 1

3 l of deionized water are placed in a 5 l glass beaker, 1000 g of 98% strength sulphuric acid are added and, while stirring, 3.28 g of antimony(III) chloride and 517.5 g of copper(II) sulphate pentahydrate are dissolved in the mixture. The mixture is subsequently made up to 5000 g with deionized water and cooled to room temperature.

This gives a sulphuric acid containing, as intended, 30 g/l of copper and 0.4 g/l of antimony.

1f) Purification of the Sulphuric Acid Composition from 1e) According to the Invention

100 ml of the monodisperse ion exchanger from 1d) are transferred to a glass column having a glass frit bottom (internal diameter=22 mm). The sulphuric acid from 1e) is passed through this glass column at a volume flow of 500 ml/h in such a way that a constant small volume of sulphuric acid is always present over the ion exchanger bed.