THE QUESTION !!!
A student wanted to find the mass of calcium carbonate in an indigestion tablet. She crushed up a tablet and added an excess of HCL acid (25cm3 of 1.00 mol/dm3). She the titrated the excess against 0.5 mol/dm3 of NaOH requiring 25.8cm3 of the NaOH. Calculate the mass off calcium carbonate in the tablet.
You can find calcium carbonate for purchase at most pharmacies, health food stores, and online retailers.
For a partly ionically bonded compound such as calcium carbonate, the gram formula mass is substituted for a mole, which technically exists only for purely covalently bonded compounds. The gram formula mass for calcium carbonate is 100.09. Therefore, 200 grams constitutes 200/100.09 or 2.00 gram formula masses of calcium carbonate, to the justified number of significant digits.
To calculate the percentage of calcium carbonate in the mixture, first find the total mass of the mixture by summing the individual masses given (1.05g + 0.69g + 1.82g = 3.56g). Then, calculate the percentage of calcium carbonate by dividing the mass of calcium carbonate by the total mass and multiplying by 100 (1.82g / 3.56g * 100 ≈ 51%). So, the percentage of calcium carbonate in the mixture is approximately 51%.
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You can find a answer fromCalcium carbonate - Wikipedia
To find the mass of calcium carbonate in a Tums tablet, you can weigh the tablet before and after a reaction that specifically targets the calcium carbonate. For example, if you react the tablet with hydrochloric acid to produce carbon dioxide gas, you can measure the mass lost due to the evolution of CO2 to calculate the mass of calcium carbonate present.
44.55 ML solution x 1L/1000ML X 0.448M HCL/1L solution X 1mole CaCO3/2 mole HCL= 0.0099792 M CaCO3 0.0099792 M CaCO3 x 217gCaCO3/1 mole CaCO3= 2.17g CaCO3 X 1000MG/1g=2170 mg of calcium carbonate are in a rolaids tablet?
You can find calcium carbonate for purchase at most pharmacies, health food stores, and online retailers.
Make a balanced chemical formula
To calculate the number of moles of stomach acid neutralized by calcium carbonate, you first need to convert the mass of calcium carbonate (600 mg) to grams (0.6 g). Then, use the molar mass of calcium carbonate (100.09 g/mol) to find the number of moles. Finally, use the balanced chemical equation to determine the moles of stomach acid neutralized.
Ca3P2 or Ca3(PO4)2 See related question below for more details on how to find empirical formulas.
This question is solved with the help of mole concept . 1 mole of anhydrous calcium carbonate weighs 40+12+48=100 gm . 1.25 mole of similar anhydrous calcium carbonate will be 100* 1.25 = 125 gm
For a partly ionically bonded compound such as calcium carbonate, the gram formula mass is substituted for a mole, which technically exists only for purely covalently bonded compounds. The gram formula mass for calcium carbonate is 100.09. Therefore, 200 grams constitutes 200/100.09 or 2.00 gram formula masses of calcium carbonate, to the justified number of significant digits.
To calculate the percentage of calcium carbonate in the mixture, first find the total mass of the mixture by summing the individual masses given (1.05g + 0.69g + 1.82g = 3.56g). Then, calculate the percentage of calcium carbonate by dividing the mass of calcium carbonate by the total mass and multiplying by 100 (1.82g / 3.56g * 100 ≈ 51%). So, the percentage of calcium carbonate in the mixture is approximately 51%.
To determine the amount of calcium carbonate in limestone, you can perform a titration using hydrochloric acid. By reacting a known mass of limestone with hydrochloric acid, you can measure the volume of acid required to neutralize the calcium carbonate. This information can then be used to calculate the amount of calcium carbonate present in the limestone sample.
Calcium Carbon and Oxygen, CaCO(4)Wait I Searched It Up and I Cant Find Any Information?
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