I'm not sure about the 37 thing but here is from NIOSH method in how to prepare 6N HCL
-pipette 25.64 mL of 11.7 N (37% HCL fuming) to 50 mL volumetric flask and top up with distilled water
GOOD LUCK
Always add acid to water.
To prepare 6N HCl from 1N HCl, you can dilute the 1N HCl by adding 6 times the volume of water to the 1N HCl solution. For example, mix 1 volume of 1N HCl with 6 volumes of water to get a final concentration of 6N HCl. Make sure to add acid to water slowly with stirring to avoid splashes and heat generation.
A 6N HCl solution refers to a solution of hydrochloric acid (HCl) where the concentration is 6 normal (6N). This means that the solution contains 6 moles of HCl per liter of solution. It is a common reagent used in laboratory settings for various chemical reactions and analyses.
Normality is equal to molarity if only a single hydrogen is involved, which fortunately it is. 35% HCl contains 350 grams of HCl per 1000 grams (or ml) of water. What is desired is 10 ml of a 6 Normal (or molar) solution. The molecular weight of HCl is 36 grams/mole, so 6 normal would be 216 grams per 1000 mls. This is equivalent to 2.16 grams per 10 milliliters (1000 ml = 1 liter). 35% HCl contains 0.350 grams per ml, so one would need 6.17 ml to give 2.16 grams. The other 3.82 ml will be pure water. Accordingly you can prepare as much quantity as you require.
6N HCl refers to a 6 molar solution of hydrochloric acid. The strength of the acid solution is determined by its concentration. It is a moderately strong acid that can cause skin irritation and burns upon contact.
To prepare a 6N NaOH solution from a 10N NaOH solution, you would dilute the 10N solution by adding water. Use the dilution formula: C1V1 = C2V2, where C1 is the initial concentration (10N), V1 is the volume of stock solution needed, C2 is the final concentration (6N), and V2 is the final volume of the solution you want to make. Calculate the volume of the 10N solution needed and add water to reach the final desired volume for a 6N NaOH solution.
To prepare 6N HCl from 1N HCl, you can dilute the 1N HCl by adding 6 times the volume of water to the 1N HCl solution. For example, mix 1 volume of 1N HCl with 6 volumes of water to get a final concentration of 6N HCl. Make sure to add acid to water slowly with stirring to avoid splashes and heat generation.
A 6N HCl solution refers to a solution of hydrochloric acid (HCl) where the concentration is 6 normal (6N). This means that the solution contains 6 moles of HCl per liter of solution. It is a common reagent used in laboratory settings for various chemical reactions and analyses.
Normality is equal to molarity if only a single hydrogen is involved, which fortunately it is. 35% HCl contains 350 grams of HCl per 1000 grams (or ml) of water. What is desired is 10 ml of a 6 Normal (or molar) solution. The molecular weight of HCl is 36 grams/mole, so 6 normal would be 216 grams per 1000 mls. This is equivalent to 2.16 grams per 10 milliliters (1000 ml = 1 liter). 35% HCl contains 0.350 grams per ml, so one would need 6.17 ml to give 2.16 grams. The other 3.82 ml will be pure water. Accordingly you can prepare as much quantity as you require.
6N HCl refers to a 6 molar solution of hydrochloric acid. The strength of the acid solution is determined by its concentration. It is a moderately strong acid that can cause skin irritation and burns upon contact.
Easy 37 +5=42/6=7 n=7
To prepare a 6N NaOH solution from a 10N NaOH solution, you would dilute the 10N solution by adding water. Use the dilution formula: C1V1 = C2V2, where C1 is the initial concentration (10N), V1 is the volume of stock solution needed, C2 is the final concentration (6N), and V2 is the final volume of the solution you want to make. Calculate the volume of the 10N solution needed and add water to reach the final desired volume for a 6N NaOH solution.
To prepare a 6N NaOH solution, you would need to dissolve 240 grams of sodium hydroxide (NaOH) pellets in enough distilled water to make 1 liter of solution. This will result in a 6N (Normal) solution of NaOH. Remember to handle NaOH with caution as it is a strong base and can cause burns.
6n+5 = 11
-5=6n+7 -5-7=6n+7-7 -12=6n -12/6=6n/6 -2=n
6n-15 = -9
6n-1 = 5
6n-1248 = -1242