NaHPO4- + Ba(NO3) >> NaNO3 + BaPO4- + H2
Na is one plus H is one plus and PO4 is three minus so it has an overall charge of
-1. This means something on the other side must have a charge. I think its the barium phosphate. Above is my best guess, don't swear by it.
When ammonium nitrate solution is mixed with aqueous potassium phosphate, a precipitate of ammonium phosphate forms due to a double displacement reaction. Ammonium phosphate is insoluble in water and therefore will appear as a solid precipitate in the solution.
The formula for strontium nitrate is Sr(NO3)2, and the formula for potassium phosphate is K3PO4. When these two compounds react together in solution, they will undergo a double displacement reaction to form strontium phosphate (Sr3(PO4)2) and potassium nitrate (KNO3).
The pH of nitrate itself is not defined, as pH measures the hydrogen ion concentration in a solution. However, when nitrate dissolves in water, it typically does not significantly affect the pH of the solution.
Hydrogen iodide can be tested using silver nitrate solution. When hydrogen iodide is bubbled through silver nitrate solution, a yellow precipitate of silver iodide is formed. This confirms the presence of iodide ions in the sample.
3Ca(NO3)2 + 2Na3PO3 >> Ca3(PO3)2 + 6NaNO3
The reaction between barium nitrate (Ba(NO3)2) and potassium phosphate (K3PO4) will form barium phosphate (Ba3(PO4)2) and potassium nitrate (KNO3). The ions left in solution will be potassium (K+) and nitrate (NO3-) ions from the potassium nitrate. The barium phosphate will precipitate out of solution.
Silver phosphate, Ag3PO4 precipitated in potassium nitrate solution (K+ and NO3-)
When ammonium nitrate solution is mixed with aqueous potassium phosphate, a precipitate of ammonium phosphate forms due to a double displacement reaction. Ammonium phosphate is insoluble in water and therefore will appear as a solid precipitate in the solution.
The formula for strontium nitrate is Sr(NO3)2, and the formula for potassium phosphate is K3PO4. When these two compounds react together in solution, they will undergo a double displacement reaction to form strontium phosphate (Sr3(PO4)2) and potassium nitrate (KNO3).
The pH of nitrate itself is not defined, as pH measures the hydrogen ion concentration in a solution. However, when nitrate dissolves in water, it typically does not significantly affect the pH of the solution.
Hydrogen iodide can be tested using silver nitrate solution. When hydrogen iodide is bubbled through silver nitrate solution, a yellow precipitate of silver iodide is formed. This confirms the presence of iodide ions in the sample.
A double displacement reaction occurs, resulting in the formation of solid calcium phosphate and soluble sodium nitrate. This is a precipitation reaction as the solid calcium phosphate is insoluble in water and precipitates out of the solution. The balanced chemical equation for this reaction is: 3Ca(NO3)2 + 2Na3PO4 -> Ca3(PO4)2 + 6NaNO3.
3Ca(NO3)2 + 2Na3PO3 >> Ca3(PO3)2 + 6NaNO3
A chemical reaction will occur, resulting in the formation of insoluble calcium phosphate (a white solid) and sodium nitrate dissolved in the solution. This reaction is a double displacement reaction where the ions switch partners.
In a nitric acid solution, you would find nitrate ions (NO3-) and hydrogen ions (H+). Nitric acid (HNO3) ionizes in water to form nitrate ions and hydrogen ions.
When sodium phosphate and iron nitrate react, they form iron phosphate and sodium nitrate. This is a double displacement reaction where the cations and anions in the reactants switch partners to form new compounds.
Sodium - Na. When silver nitrate is mixed with Sodium Hydroxide, Sodium Iodide, Sodium Phosphate a precipitate forms.