How do you balance the chemical equation C2H5OH O2 CO2 H2O?

Answer 1

C4H10 + 13/2O2 ---> 4CO2 + 5H2O

(1) First balance the carbon atoms: There are 4 on the left, so you'll need 4 on the right. So put a 4 in front of CO2

(2) Next balance the hydrogen atoms: there are 10 on the left, so you'll need 10 on the right. Since you have a water molecule, put 5 in front of H2O (5*2 = 10).

(3) Finally balance the oxygen atoms: on the right you have 4*2 (from the carbon dioxide) + 5*1 (from the water) = 8+5 or 13. So you now need 13 atoms of oxygen on the left. So put 13/2 in front of O2 (13/2 * 2 = 13)

(4) Now get rid of the fraction in front of O2 by multiplying all the coefficients by 2, to get your final balanced equation:

2C4H10 + 13O2 ---> 8CO2 + 10H2O

Answer 2

To balance the chemical equation for the combustion of ethanol (C2H5OH) with oxygen (O2) to form carbon dioxide (CO2) and water (H2O), you need to ensure that the number of atoms for each element is the same on both sides of the equation. Start by balancing the carbon atoms, then the hydrogen atoms, and finally the oxygen atoms. The balanced equation will be: C2H5OH + 3 O2 -> 2 CO2 + 3 H2O

Answer 3

Unbalanced: C2H4 + O2 → H2O + CO2

Balanced: C2H4 + 3O2 → 2H2O + 2CO2

Answer 4

2C2H6 + 7O2 -> 4CO2 + 6H2O

Always balance O2 last and pay attention to the hydrocarbon arrangement.

Answer 5

The chemical equation is:
C2H5OH + O2 = 2 CO2 + 3 H2O

Answer 6

2 C2H2 + 5 O2 → 4 CO2 + 2 H2O

Answer 7

C2h4o2 + 2 o2 = 2 co2 + 2 h2o