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Write what you have first, Zn + FeCl3 ---> ZnCl2 + Fe

Everything matches up except the Cl, we have 3 on the left and 2 on the right. To balance, we look for a common factor, which is 6. So we multiply the FeCl3 by 2 and the ZnCl2 by 3.

Zn + 2FeCl3 ---> 3ZnCl2 + Fe

Now we have 6 Cl on both sides but the Zn and Fe are unbalanced. Now we have 2 Fe on the left and 1 on the right. We have 1 Zn on the left and 3 on the right. So we multiply the reactant Zn by 3 and the product Fe by 2.

3Zn + 2FeCl3 ---> 3ZnCl2 + 2Fe

Zn Zn Zn + ClFeCl ClFeCl ---> ClZnCl ClZnCl ClZnCl + Fe Fe

Cl Cl

3 Zn, 6 Cl, 2 Fe ---> 6 Cl, 3 Zn, 2 Fe

The same amount of each atom is on each side so it's balanced.

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