C4H10 + 13/2O2 ---> 4CO2 + 5H2O
(1) First balance the carbon atoms: There are 4 on the left, so you'll need 4 on the right. So put a 4 in front of CO2
(2) Next balance the hydrogen atoms: there are 10 on the left, so you'll need 10 on the right. Since you have a water molecule, put 5 in front of H2O (5*2 = 10).
(3) Finally balance the oxygen atoms: on the right you have 4*2 (from the carbon dioxide) + 5*1 (from the water) = 8+5 or 13. So you now need 13 atoms of oxygen on the left. So put 13/2 in front of O2 (13/2 * 2 = 13)
(4) Now get rid of the fraction in front of O2 by multiplying all the coefficients by 2, to get your final balanced equation:
2C4H10 + 13O2 ---> 8CO2 + 10H2O
To balance the chemical equation for the combustion of ethanol (C2H5OH) with oxygen (O2) to form carbon dioxide (CO2) and water (H2O), you need to ensure that the number of atoms for each element is the same on both sides of the equation. Start by balancing the carbon atoms, then the hydrogen atoms, and finally the oxygen atoms. The balanced equation will be: C2H5OH + 3 O2 -> 2 CO2 + 3 H2O
Unbalanced: C2H4 + O2 → H2O + CO2
Balanced: C2H4 + 3O2 → 2H2O + 2CO2
2C2H6 + 7O2 -> 4CO2 + 6H2O
Always balance O2 last and pay attention to the hydrocarbon arrangement.
The chemical equation is:
C2H5OH + O2 = 2 CO2 + 3 H2O
2 C2H2 + 5 O2 → 4 CO2 + 2 H2O
C2h4o2 + 2 o2 = 2 co2 + 2 h2o
This is a balanced chemical equation for the combustion of ethanol (C2H5OH) in the presence of oxygen (O2) to form carbon dioxide (CO2) and water (H2O): C2H5OH + 3O2 → 2CO2 + 3H2O
The reaction between C2H5OH (ethanol) and O2 (oxygen) is combustion, which produces carbon dioxide (CO2) and water (H2O) as products. The balanced chemical equation for the reaction is: C2H5OH + 3O2 → 2CO2 + 3H2O
The chemical equation for the reaction of ethanol (C2H5OH) with oxygen (O2) to form carbon dioxide (CO2) and water (H2O) is: C2H5OH + 3O2 -> 2CO2 + 3H2O
The balanced chemical equation for the reaction is 2 C2H5OH + 3 O2 → 2 CO2 + 3 H2O. This means that two molecules of ethanol (C2H5OH) react with three molecules of oxygen (O2) to produce two molecules of carbon dioxide (CO2) and three molecules of water (H2O).
I believe the balanced chemical equation isC2H5OH+3O2 ---> 2CO2+3H2O the amount of energy relased from the equation is -1409kJ/molhowever I tried to calculate it out myself with a bond energy table i received from my professor and ended up with the number -1283kJ/mol...close enough
Burning alcohol First 1 C2H5OH + O2 -> 2 CO2 + 3 H2O to balance the just the carbons and hydrogens now count the oxygens in the products 4+3=7 and determine the number of oxygens: 1 C2H5OH +3 O2 -> 2 CO2 + 3 H2O
C2H5OH + 3 O2 =Heat=> 2 CO2 + 3 H2O
This equation is:C2H5OH + 3 O2 = 2 CO2 + 3 H2O
This is a balanced chemical equation for the combustion of ethanol (C2H5OH) in the presence of oxygen (O2) to form carbon dioxide (CO2) and water (H2O): C2H5OH + 3O2 → 2CO2 + 3H2O
The balanced chemical equation is: CO2 + C → 2CO
The balanced chemical equation for the reaction involving acetic anhydride (C4H6O3) is: 2C4H6O3 → 4CH3COOH + (CH3CO)2O
The balanced chemical equation for cellular respiration is C6H12 O6+ O2--> CO2 + H20 + ATP
CO2 is not an equation, so it cannot be balanced. It is a chemical formula.
The balanced chemical equation for the reaction of C2H6O (ethanol) with O2 (oxygen) to form CO2 (carbon dioxide) and H2O (water) is: C2H6O + 3O2 → 2CO2 + 3H2O.
The balanced chemical equation for the reaction between magnesium (Mg) and carbon dioxide (CO2) is: 2 Mg + CO2 -> 2 MgO + C
I believe the balanced chemical equation isC2H5OH+3O2 ---> 2CO2+3H2O the amount of energy relased from the equation is -1409kJ/molhowever I tried to calculate it out myself with a bond energy table i received from my professor and ended up with the number -1283kJ/mol...close enough
This equation is C2H5OH + 3 O2 -> 2 CO2 + 3 H2O.