To calculate 250 ppm (parts per million) chlorine solution in water, you would need 250 parts of chlorine for every 1 million parts of water. This can be simplified to 1 part of chlorine for every 4000 parts of water (since 1 million divided by 250 is 4000). Therefore, you would mix 1 unit of chlorine with 4000 units of water to achieve a 250 ppm chlorine solution.
To find the final concentration, we calculate the moles of KOH initially present in the 45.0 ml solution, then add the moles from the additional 250 ml of water. We then divide the total moles by the final volume (45.0 ml + 250 ml) to get the concentration. The concentration of the final solution would be less than 4.2 M KOH due to dilution when water is added.
To make a 3 Molar solution of potassium chloride in 250 milliliters: Calculate the mass of potassium chloride needed using its molar mass. Dissolve this mass of potassium chloride in a small amount of water, then add water to bring the total volume to 250 ml. Stir to ensure complete mixing and dissolve the potassium chloride completely.
To find the concentration of the final solution, you need to calculate the total moles of KOH before and after dilution. The initial moles of KOH can be found using the initial volume and concentration. Then, calculate the final volume of the solution after dilution and use it to determine the final concentration of KOH.
The final volume of the solution is 375 mL (125 mL HCl + 250 mL water). As the water does not contribute to the molarity of the solution, the moles of HCl remain the same. Thus, the molarity of the final solution is 0.251 mol / (0.375 L) = 0.670 M.
The total weight of the saltwater solution is 250 ounces (200 ounces of water + 50 ounces of salt). The percentage of salt in the solution can be calculated as (50 ounces / 250 ounces) * 100 = 20%. Therefore, the salt weight represents 20% of the whole solution.
To make a 20 ppm chlorine solution for a 250 gallon spa using liquid household bleach, you would need to add approximately 1.8 fluid ounces of 8.25% bleach to the spa water. This calculation assumes that the bleach is added to a freshly filled spa with no existing chlorine in the water. Be sure to test and adjust the chlorine levels accordingly before using the spa.
To find the final concentration, we calculate the moles of KOH initially present in the 45.0 ml solution, then add the moles from the additional 250 ml of water. We then divide the total moles by the final volume (45.0 ml + 250 ml) to get the concentration. The concentration of the final solution would be less than 4.2 M KOH due to dilution when water is added.
To make a 3 Molar solution of potassium chloride in 250 milliliters: Calculate the mass of potassium chloride needed using its molar mass. Dissolve this mass of potassium chloride in a small amount of water, then add water to bring the total volume to 250 ml. Stir to ensure complete mixing and dissolve the potassium chloride completely.
To find the concentration of the final solution, you need to calculate the total moles of KOH before and after dilution. The initial moles of KOH can be found using the initial volume and concentration. Then, calculate the final volume of the solution after dilution and use it to determine the final concentration of KOH.
To prepare a 100 ppm stock solution of nickel nitrate in 250 ml, first calculate the mass of nickel nitrate needed. Nickel nitrate (Ni(NO3)2·6H2O) has a molar mass of approximately 290.79 g/mol. For a 100 ppm solution, you need 100 mg of nickel nitrate in 1 liter, so for 250 ml, you would require 25 mg of nickel nitrate. Weigh out 25 mg of nickel nitrate, dissolve it in a small volume of distilled water, and then dilute the solution to a final volume of 250 ml with distilled water in a volumetric flask.
The final volume of the solution is 375 mL (125 mL HCl + 250 mL water). As the water does not contribute to the molarity of the solution, the moles of HCl remain the same. Thus, the molarity of the final solution is 0.251 mol / (0.375 L) = 0.670 M.
the largest single use of water is by industries. it takes about 270 tones of water to make a tons of steels and about 250 tone of water paper .
The total weight of the saltwater solution is 250 ounces (200 ounces of water + 50 ounces of salt). The percentage of salt in the solution can be calculated as (50 ounces / 250 ounces) * 100 = 20%. Therefore, the salt weight represents 20% of the whole solution.
the largest single use of water is by industries. it takes about 270 tones of water to make a tons of steels and about 250 tone of water paper .
The water volume is 212,5 mL.
64 (g) / 250 (mL) = 0.256 g/mL = 256 g/L
(volume) x (density) = mass (250 ml) x (1 g/ml) = 250 grams 1 ml = 1 cc