0
To calculate 250 ppm (parts per million) chlorine solution in water, you would need 250 parts of chlorine for every 1 million parts of water. This can be simplified to 1 part of chlorine for every 4000 parts of water (since 1 million divided by 250 is 4000). Therefore, you would mix 1 unit of chlorine with 4000 units of water to achieve a 250 ppm chlorine solution.
What else can I help you with?
What would be the concentration of a solution made by adding 250 ml of water to 45.0 m of 4.2 M KOH?
To find the final concentration, we calculate the moles of KOH initially present in the 45.0 ml solution, then add the moles from the additional 250 ml of water. We then divide the total moles by the final volume (45.0 ml + 250 ml) to get the concentration. The concentration of the final solution would be less than 4.2 M KOH due to dilution when water is added.
How I will make 3 Molar solution of potassium chloride in 250 milliliter?
To make a 3 Molar solution of potassium chloride in 250 milliliters: Calculate the mass of potassium chloride needed using its molar mass. Dissolve this mass of potassium chloride in a small amount of water, then add water to bring the total volume to 250 ml. Stir to ensure complete mixing and dissolve the potassium chloride completely.
What would be the concentration of a solution made by adding 250 mL of water to 45.0 mL of 4.2 M KOH?
To find the concentration of the final solution, you need to calculate the total moles of KOH before and after dilution. The initial moles of KOH can be found using the initial volume and concentration. Then, calculate the final volume of the solution after dilution and use it to determine the final concentration of KOH.
What is the molarity of a solution prepared by combining 125 mL of 0.251 molar HCl with 250 mL of pure water?
The final volume of the solution is 375 mL (125 mL HCl + 250 mL water). As the water does not contribute to the molarity of the solution, the moles of HCl remain the same. Thus, the molarity of the final solution is 0.251 mol / (0.375 L) = 0.670 M.
In science class we made salt water with 200 ounces of water and 50 ounces of salt. what is the pecentage of salt weight of the whole?
The total weight of the saltwater solution is 250 ounces (200 ounces of water + 50 ounces of salt). The percentage of salt in the solution can be calculated as (50 ounces / 250 ounces) * 100 = 20%. Therefore, the salt weight represents 20% of the whole solution.
How do you make a 20 ppm chlorine solution for a 250 gallon spa using liquid household bleach?
To make a 20 ppm chlorine solution for a 250 gallon spa using liquid household bleach, you would need to add approximately 1.8 fluid ounces of 8.25% bleach to the spa water. This calculation assumes that the bleach is added to a freshly filled spa with no existing chlorine in the water. Be sure to test and adjust the chlorine levels accordingly before using the spa.
What would be the concentration of a solution made by adding 250 ml of water to 45.0 m of 4.2 M KOH?
To find the final concentration, we calculate the moles of KOH initially present in the 45.0 ml solution, then add the moles from the additional 250 ml of water. We then divide the total moles by the final volume (45.0 ml + 250 ml) to get the concentration. The concentration of the final solution would be less than 4.2 M KOH due to dilution when water is added.
How I will make 3 Molar solution of potassium chloride in 250 milliliter?
To make a 3 Molar solution of potassium chloride in 250 milliliters: Calculate the mass of potassium chloride needed using its molar mass. Dissolve this mass of potassium chloride in a small amount of water, then add water to bring the total volume to 250 ml. Stir to ensure complete mixing and dissolve the potassium chloride completely.
What would be the concentration of a solution made by adding 250 mL of water to 45.0 mL of 4.2 M KOH?
To find the concentration of the final solution, you need to calculate the total moles of KOH before and after dilution. The initial moles of KOH can be found using the initial volume and concentration. Then, calculate the final volume of the solution after dilution and use it to determine the final concentration of KOH.
How do you prepare 100 ppm stock solution of nickel nitrate in 250 ml?
To prepare a 100 ppm stock solution of nickel nitrate in 250 ml, first calculate the mass of nickel nitrate needed. Nickel nitrate (Ni(NO3)2·6H2O) has a molar mass of approximately 290.79 g/mol. For a 100 ppm solution, you need 100 mg of nickel nitrate in 1 liter, so for 250 ml, you would require 25 mg of nickel nitrate. Weigh out 25 mg of nickel nitrate, dissolve it in a small volume of distilled water, and then dilute the solution to a final volume of 250 ml with distilled water in a volumetric flask.
What is the molarity of a solution prepared by combining 125 mL of 0.251 molar HCl with 250 mL of pure water?
The final volume of the solution is 375 mL (125 mL HCl + 250 mL water). As the water does not contribute to the molarity of the solution, the moles of HCl remain the same. Thus, the molarity of the final solution is 0.251 mol / (0.375 L) = 0.670 M.
What is the solution for Industrialization?
the largest single use of water is by industries. it takes about 270 tones of water to make a tons of steels and about 250 tone of water paper .
In science class we made salt water with 200 ounces of water and 50 ounces of salt. what is the pecentage of salt weight of the whole?
The total weight of the saltwater solution is 250 ounces (200 ounces of water + 50 ounces of salt). The percentage of salt in the solution can be calculated as (50 ounces / 250 ounces) * 100 = 20%. Therefore, the salt weight represents 20% of the whole solution.
What is the solution for industrial pollution?
the largest single use of water is by industries. it takes about 270 tones of water to make a tons of steels and about 250 tone of water paper .
How many mL of water are present in 250 mL of a 15 percent by volume aqueous hydrochloric acid solution?
The water volume is 212,5 mL.
What is the concentration of a solution consisting of 64 grams of calcium chloride in 250 mL of water?
64 (g) / 250 (mL) = 0.256 g/mL = 256 g/L
How can you calculate the mass or water when it is in a glass?
(volume) x (density) = mass (250 ml) x (1 g/ml) = 250 grams 1 ml = 1 cc
