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To change a 5N HClO4 solution to a 0.25N HClO4 solution, you will need to dilute the original solution with water. Calculate the volume of the original solution needed to make the final volume with a concentration of 0.25N. Add the calculated volume of water and mix well to achieve the desired concentration.
What else can I help you with?
How do you make 1N hydrochloric acid from 5N hydrochloric acid?
Take 200 mls and dilute to exactly 1000 mls in a volumetric flask Applying the formula c1v1 = c2v2 1(1000) = 5V V=200CM3 Thus take 200cm3 of 5N HCl and make up to 1000cm3 with distilled water
How do you make HCl 5 normal?
To make 5N HCl solution, add the appropriate volume of concentrated hydrochloric acid (usually around 37% concentration) to water to achieve the desired normality. Use proper safety precautions as hydrochloric acid is corrosive and should always be added to water, not the other way around, to avoid splattering. It's recommended to double-check calculations and volumes to ensure accuracy.
What is the preparation of nessler's reagent?
Dissolve 50g of KI in the smallest possible quantity of cold water (50 ml). Add a saturated solution of mercuric chloride (about 22g in 350ml of water will be needed) until an excess is indicated by the formation of a precipitate. Then add 200ml of 5N NaOH and dilute to 1 liter. Let settle, and draw off the clear liquid.
How do you make 0.02N sulfuric acid solution?
I would like to dilute some 5N sulfuric acid with water, and make 0.1N sulfuric acid solution. I want 1000ml of 0.1N . I think it's a 50 to 1 ration, but just want to make sure. <Volume of concentrated> x <Concentration of Concentrated> = <Volume of dilute> x <Concentration of dilute> Therefore, <Volume of concentrated> = <Volume of dilute> x <Concentration of dilute> / <Concentration of dilute> = 1000 mL x 0.1 N / 5N = 20 mL. Meaning: Dilute 20 mL of the 5N H2SO4 to 1000 mL in a volumetetric flask will give you 1000 mLs of 0.1 N H2SO4 (aq.).
How do make a 5.25N sulfuric acid solution from concentrated sulfuric acid solution?
con.H2SO4 is 98%(v/v)ie 980ml/litre.or 980X1.84(specific gravity of H2So4)ie wt/litre is 1803.2Normality= wt per litre/ Eq.wtie 1803.2/49=36.8 NHence con H2So4 is 36.8 NTo prepare 5 N , It has be diluted 7.36 times with water68
What is the solution of the equation 5n - 3 equals 17?
Previous poster was very wrong, 5n-3=17 5n=20 n=4
What is the solution to x equals 3 MOD 5?
The solution set is x = 5n + 3 where n is any integer.
What is the GCF of 5n and 5 mn?
The GCF is 5n.
What is the property of 5n equals 5n?
what does the expresstion 5n represent
What is 5m-5n plus 5m plus 5n?
5m-5n+5m+5n When simplified: 10m
What is the answer for 30 equals 5n?
5n=30n=30/5n=6
How do you prepare 5N hcl solution?
520 ml of HCl in 480 ml of water=1000ml = 5 N
What is the answer to -5n- -2 equals 27?
-5n - (-2) = 27 -5n + 2 = 27 -5n + 2 - 2 = 27 - 2 -5n = 25 -5n/-5 = 25/-5 n = -5
1 over 5n plus 4 over 5n minus 1 over 5n?
4 over 5n
What the answer to (n plus 7)5n?
The expression ( (n + 7)5n ) can be simplified by distributing ( 5n ) to both terms inside the parentheses. This results in ( 5n \cdot n + 5n \cdot 7 ), which simplifies to ( 5n^2 + 35n ). Therefore, the answer is ( 5n^2 + 35n ).
Solve for n in 5n - 25 equals 10?
5n-25 = 10 5n = 10+25 5n = 35 n = 7
How do you solve -5n plus 9 equals -46?
-5n+9=-46 -5n+9-9=-46-9 -5n=-55 -5n/-5=-55/-5 n=11
