How do you draw 2-4-diethyl-4-ethoxyhexane?

Answer 1

To draw 2,4-diethyl-4-ethoxyhexane, start by drawing a hexane chain (6 carbon atoms in a straight line). Then, add two ethyl groups (CH3CH2-) at the 2nd and 4th carbon positions. Next, add an ethoxy group (-OCH2CH3) at the 4th carbon position. Ensure that all carbon atoms have the appropriate number of hydrogen atoms attached to satisfy their valency.

Answer 2

Well, honey, you start by drawing a hexagon to represent the six carbon atoms in the main chain. Then, you slap on two ethyl groups at the second carbon atom, and two ethoxy groups at the fourth carbon atom. Don't forget to add in those hydrogen atoms to keep everything in check. Voila, you've got yourself a sassy little molecule of 2,4-diethyl-4-ethoxyhexane!

Answer 3

Basically, it's a hexene molecule (6 carbons, C-C-C-C-C=C, the double bond comes from it being an ALKENE, this is obvious from the -ene on the end of the word hexene) with two(di-) methyl groups on it (Methyl being CH3). the numbers describe where exactly the methyl groups and hexene double bond are located on the structure. If you number each carbon 1 to 6 from right to left, you know which carbon to put the methyls on (3-4). The 2 states where the double bond is located, which is between carbon 2 and 3. Here's an example.

C1-C2=C3-C4-C5-C6

Each number shows where exactly each substituent group goes. I put the double bond in at 2, the methyl groups (CH3) would be bonded by their carbon to carbons 3 and 4 on the hexene chain above.

I am unable to draw an example of this molecule's shape and I can't find a picture of it on the internet but so long as you draw in a methyl group on carbon's 3 and 4 in the numbered Hexene chain above, you should have the correct structure.

Hope this helped.

Answer 4

To draw 2-4-diethyl-4-ethoxyhexane, start by drawing hexane. Now place an ethyl group on the second hexane and the fourth. Also, place an O atom. single bonded to the 4th carbon. Bond an ethyl group to the O atom.

Answer 5

To draw 2,4-diethyl-4-ethoxyhexane, start by drawing a six-carbon chain. Add an ethyl group (CH3CH2-) at the 2nd and 4th carbon positions. Finally, add an ethoxy group (CH3CH2O-) at the 4th carbon position. Remember to position the groups correctly to reflect their numbering.

Answer 6

i am not sure but i think it is : c c c c c c c c

Answer 7

It should be C7H16

Answer 8

CH3-CH(CH3)-CH(CH3)-CH2-CH(CH3)-CH3