Use the letter X instead. Double click it once you have finished placing it and then clear and write in the letter R.
The structure for 2-bromo-3-methyl-3-heptanol looks as follows: First draw a heptane chain. Single bond a bromine to the 2nd carbon. single bond a methyl group to the 3 carbon. Single bond a hydoxyl group to the third carbon as well.
CH3-CH(CH3)-CH2-CH2-CH3, 2-methylpentane
Firstly you must draw the pentagon then you count the number start at downward. Then you write CH3 for second and C6H5 for third place
The inductive effect is when atoms within molecules donate some of their charge throughout the molecule. For example, a strongly electron withdrawing group, such as a nitro group (NO2) or a carbonyl (CO), will draw electrons away from the rest of the molecule, making other atoms more positive. An electron donating group, such as a methoxide (OCH3) or just a methyl group (CH3) will donate their charges to other atoms within that molecule. A carbon with a methoxide group next to it will be delta positive (have a relative positive charge compared with a neutral carbon atom), whereas a carbon with a carbonyl next to it will be delta minus (have a relative negative charge compared with a neutral carbon atom).
Basically, it's a hexene molecule (6 carbons, C-C-C-C-C=C, the double bond comes from it being an ALKENE, this is obvious from the -ene on the end of the word hexene) with two(di-) methyl groups on it (Methyl being CH3). the numbers describe where exactly the methyl groups and hexene double bond are located on the structure. If you number each carbon 1 to 6 from right to left, you know which carbon to put the methyls on (3-4). The 2 states where the double bond is located, which is between carbon 2 and 3. Here's an example. C1-C2=C3-C4-C5-C6 Each number shows where exactly each substituent group goes. I put the double bond in at 2, the methyl groups (CH3) would be bonded by their carbon to carbons 3 and 4 on the hexene chain above. I am unable to draw an example of this molecule's shape and I can't find a picture of it on the internet but so long as you draw in a methyl group on carbon's 3 and 4 in the numbered Hexene chain above, you should have the correct structure. Hope this helped.
The structure for 2-bromo-3-methyl-3-heptanol looks as follows: First draw a heptane chain. Single bond a bromine to the 2nd carbon. single bond a methyl group to the 3 carbon. Single bond a hydoxyl group to the third carbon as well.
To begin with, octane is a chain of 8 carbons. If you were to draw these eight carbons in a row and number them 1-8, then the numbers corresponding to the substituents (chloro, ethyl and methyl) will show you where to put them. Off of the fifth carbon from one end (make sure you are consistent with which end you use!) is Cl Off of the third carbon is the ethyl group (CH2-CH3) and off of the fourth is the methyl group (CH3)
CH3-CH(CH3)-CH2-CH2-CH3, 2-methylpentane
Firstly you must draw the pentagon then you count the number start at downward. Then you write CH3 for second and C6H5 for third place
c the book mastering c
The inductive effect is when atoms within molecules donate some of their charge throughout the molecule. For example, a strongly electron withdrawing group, such as a nitro group (NO2) or a carbonyl (CO), will draw electrons away from the rest of the molecule, making other atoms more positive. An electron donating group, such as a methoxide (OCH3) or just a methyl group (CH3) will donate their charges to other atoms within that molecule. A carbon with a methoxide group next to it will be delta positive (have a relative positive charge compared with a neutral carbon atom), whereas a carbon with a carbonyl next to it will be delta minus (have a relative negative charge compared with a neutral carbon atom).
Basically, it's a hexene molecule (6 carbons, C-C-C-C-C=C, the double bond comes from it being an ALKENE, this is obvious from the -ene on the end of the word hexene) with two(di-) methyl groups on it (Methyl being CH3). the numbers describe where exactly the methyl groups and hexene double bond are located on the structure. If you number each carbon 1 to 6 from right to left, you know which carbon to put the methyls on (3-4). The 2 states where the double bond is located, which is between carbon 2 and 3. Here's an example. C1-C2=C3-C4-C5-C6 Each number shows where exactly each substituent group goes. I put the double bond in at 2, the methyl groups (CH3) would be bonded by their carbon to carbons 3 and 4 on the hexene chain above. I am unable to draw an example of this molecule's shape and I can't find a picture of it on the internet but so long as you draw in a methyl group on carbon's 3 and 4 in the numbered Hexene chain above, you should have the correct structure. Hope this helped.
Soap is not a pure compound.
Difficult to draw here, but let's try to describe: Three methyl groups (CH3-) and one H- atom bonded to one central C atom, then you'll get something like this: . . . .H CH3-C-CH3 . . . .CH3
pretty sure it's green with your chemistry.
If you go to Insert Shapes and the Callouts group, you will find the speech bubble. It can then be clicked on and then you draw it out onto the worksheet.If you go to Insert Shapes and the Callouts group, you will find the speech bubble. It can then be clicked on and then you draw it out onto the worksheet.If you go to Insert Shapes and the Callouts group, you will find the speech bubble. It can then be clicked on and then you draw it out onto the worksheet.If you go to Insert Shapes and the Callouts group, you will find the speech bubble. It can then be clicked on and then you draw it out onto the worksheet.If you go to Insert Shapes and the Callouts group, you will find the speech bubble. It can then be clicked on and then you draw it out onto the worksheet.If you go to Insert Shapes and the Callouts group, you will find the speech bubble. It can then be clicked on and then you draw it out onto the worksheet.If you go to Insert Shapes and the Callouts group, you will find the speech bubble. It can then be clicked on and then you draw it out onto the worksheet.If you go to Insert Shapes and the Callouts group, you will find the speech bubble. It can then be clicked on and then you draw it out onto the worksheet.If you go to Insert Shapes and the Callouts group, you will find the speech bubble. It can then be clicked on and then you draw it out onto the worksheet.If you go to Insert Shapes and the Callouts group, you will find the speech bubble. It can then be clicked on and then you draw it out onto the worksheet.If you go to Insert Shapes and the Callouts group, you will find the speech bubble. It can then be clicked on and then you draw it out onto the worksheet.
Impossible to draw directly with this text editor, but try: Take one 6-membered ring of single bonded -CH2- groups (hexagonal) and then replace one H- atom (out of 12) by one methyl CH3- group: there you are CH3-C6H11