0.72 Molar dibasic potassium phosphate (125.410 grams/liter K2HPO4, molecular weight=174.18 grams/mole).
H2PO3 is a weak acid. It can donate a proton, making it acidic. It is not considered a base as it does not readily accept protons.
The Oxidation number is found when you divide then multiply the multivascular equation of the H2PO3 proportion and find the percentage of 115 then square your answer and add it to your proportion.
The conjugate base of H2PO3- ion is HPO3-2 ion.
H2po3 ^-1
Yes, H2PO3- is amphiprotic because it can donate and accept protons. It can donate a proton to act as an acid, forming HPO32- or accept a proton to act as a base, forming H3PO3.
H2PO3 is a weak acid. It can donate a proton, making it acidic. It is not considered a base as it does not readily accept protons.
The Oxidation number is found when you divide then multiply the multivascular equation of the H2PO3 proportion and find the percentage of 115 then square your answer and add it to your proportion.
The conjugate base of H2PO3- ion is HPO3-2 ion.
There are 7 atoms in H2PO3, comprising of 2 hydrogen atoms, 1 phosphorus atom, and 4 oxygen atoms.
H2po3 ^-1
To determine the equivalent weight from the molecular weight, you need to divide the molecular weight by the valence (or charge) of the compound. For example, for a compound with a molecular weight of 100 g/mol and a valence of 2, the equivalent weight would be 50 g/equiv.
Yes, H2PO3- is amphiprotic because it can donate and accept protons. It can donate a proton to act as an acid, forming HPO32- or accept a proton to act as a base, forming H3PO3.
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The chemical formulaof this ion is (H2PO3)-.
The conjugate base of H3PO3 is H2PO3-, which forms when H3PO3 loses a proton.
The ionization reaction for phosphorous acid (H3PO3) is: H3PO3 -> H+ + H2PO3-
the equivalent weight of chlorine is 35.453, which is also it's atomic weight.