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WHAT IS THE MOLARITY OF 0.05 OF NAOH IN 10 ML NAOH?
To find the molarity, you need to know the amount in moles of NaOH and the volume in liters. First, convert 10 mL to liters by dividing by 1000 (10 mL = 0.01 L). Then, calculate the number of moles of NaOH using the molarity formula, Molarity = moles/volume. Given that you have 0.05 moles of NaOH and a volume of 0.01 L, the molarity would be 5 M.
How 2.60 moles of LiCl is dissolved in 230 mL of water What is the resulting molarity?
To find the molarity, first calculate the number of moles of LiCl in 230 mL of water. Then, divide the moles of LiCl by the volume of water in liters (230 mL = 0.23 L) to get the molarity. In this case, 2.60 moles of LiCl in 0.23 L of water would result in a molarity of 11.30 mol/L.
A student carefully diluted 25.0 ml 0.6 M NaOH solution in 475 ml of distilled water What is the molarity of the diluted solution of base?
Assuming that the 25.0 ml are added to the 475 ml of water, not diluted to that volume:Moles of NaOH in the original 25 ml = 25/1000 x 0.6 = 0.015 moles Final volume = 25 + 475 ml = 500 ml. We have 0.015 moles in 500 ml, so 0.03 moles in a litre, Molarity = 0.03.
What is the concentration of a household ammonia cleaning solution if 49.90 ml of 0.5900m hci is required to neutralize 25.00 ml of the solution?
The molarity of the ammonia solution is 0.295 M. This is calculated by finding the moles of HCl (0.0294 mol) from the volume and molarity given and then using the equation moles = Molarity * Volume to find the molarity of the ammonia solution.
What is the molarity of a solution if 48.0 mL of a 0.220 M solution is required to neutralize a 25.0-mL sample of the solution?
To find the molarity of the solution, you can use the formula M1V1 = M2V2, where M1 is the initial molarity, V1 is the initial volume, M2 is the final molarity, and V2 is the final volume. In this case, the initial molarity (M1) is 0.220 M, the initial volume (V1) is 48.0 mL, and the final volume (V2) is 25.0 mL. By rearranging the formula to solve for M2, you would get M2 = (M1V1) / V2. Plugging in the values, you would get M2 = (0.220 M * 48.0 mL) / 25.0 mL = 0.4224 M. Therefore, the molarity of the solution is 0.4224 M.
What is ml into g?
if I have .60 molarity how do i find out haow many ml I have
WHAT IS THE MOLARITY OF 0.05 OF NAOH IN 10 ML NAOH?
To find the molarity, you need to know the amount in moles of NaOH and the volume in liters. First, convert 10 mL to liters by dividing by 1000 (10 mL = 0.01 L). Then, calculate the number of moles of NaOH using the molarity formula, Molarity = moles/volume. Given that you have 0.05 moles of NaOH and a volume of 0.01 L, the molarity would be 5 M.
How 2.60 moles of LiCl is dissolved in 230 mL of water What is the resulting molarity?
To find the molarity, first calculate the number of moles of LiCl in 230 mL of water. Then, divide the moles of LiCl by the volume of water in liters (230 mL = 0.23 L) to get the molarity. In this case, 2.60 moles of LiCl in 0.23 L of water would result in a molarity of 11.30 mol/L.
A student carefully diluted 25.0 ml 0.6 M NaOH solution in 475 ml of distilled water What is the molarity of the diluted solution of base?
Assuming that the 25.0 ml are added to the 475 ml of water, not diluted to that volume:Moles of NaOH in the original 25 ml = 25/1000 x 0.6 = 0.015 moles Final volume = 25 + 475 ml = 500 ml. We have 0.015 moles in 500 ml, so 0.03 moles in a litre, Molarity = 0.03.
What is the concentration of a household ammonia cleaning solution if 49.90 ml of 0.5900m hci is required to neutralize 25.00 ml of the solution?
The molarity of the ammonia solution is 0.295 M. This is calculated by finding the moles of HCl (0.0294 mol) from the volume and molarity given and then using the equation moles = Molarity * Volume to find the molarity of the ammonia solution.
What is the molarity of a solution if 48.0 mL of a 0.220 M solution is required to neutralize a 25.0-mL sample of the solution?
To find the molarity of the solution, you can use the formula M1V1 = M2V2, where M1 is the initial molarity, V1 is the initial volume, M2 is the final molarity, and V2 is the final volume. In this case, the initial molarity (M1) is 0.220 M, the initial volume (V1) is 48.0 mL, and the final volume (V2) is 25.0 mL. By rearranging the formula to solve for M2, you would get M2 = (M1V1) / V2. Plugging in the values, you would get M2 = (0.220 M * 48.0 mL) / 25.0 mL = 0.4224 M. Therefore, the molarity of the solution is 0.4224 M.
What is the molarity of the solution obtained by diluting 12.500 mL of a 5.42 M calcium bromide solution to 500.0 mL?
For problems like these, (dilution/concentration) it is usually best to find out how many moles of solute you are working with. To do this, multiply the number of Liters you have by the Molarity (mol/L) of the solution:(.0125L)*(5.42M)= .0678mol (12.5mL=.0125L because there are 1000mL in 1L)Now that we know how many moles of calcium bromide we have, we can find the molarity of the new solution if it is .5L. Because molarity is just mol/L, we can just divide the amount of moles by .5, which gets us:(.0678mol)/(0.5L)= 0.136M
What is the molarity of 140 g of KCl dissolved in 600. mL of water.?
The molarity is 0,388.
What is the molarity of the NaOH solution if 25.0 mL of the solution is required to neutralize 35.0 mL of a 0.20 M HCl solution?
To find the molarity of the NaOH solution, use the formula M1V1 M2V2. Given that V1 25.0 mL, V2 35.0 mL, and M2 0.20 M, you can calculate M1 to be 0.14 M.
What is the molarity of 70 grams of sulfuric acid in 280 mL solution.?
To find the molarity, first convert the mass of sulfuric acid to moles by dividing by its molar mass (98.08 g/mol). Then, calculate the molarity by dividing the moles of sulfuric acid by the volume of the solution in liters (280 mL = 0.28 L). Molarity = moles of solute / liters of solution.
you have 500 ml of a 1.5 m hcl solution (acid). if there is 250 ml of koh solution present (base). what will be the molarity of the koh (base)?
To find the molarity of the KOH solution, we need to know the concentration of the KOH solution in moles per liter. Without this information, we cannot calculate the molarity.
If 400.0 mL of 0.420 M NaCl are mixed with 110.0 mL of 0.240 M NaCl what is the molarity of the final solution?
In 400 ml of the 0.420 M NaCl there are 0.1680 moles of NaCl.In 110 ml of the 0.240 M NaCl there are 0.0264 moles of NaCl.There are 0.1944 moles of NaCl in 510 ml of solution. Dividing 0.1944 moles by 0.510 l gives 0.381 mole/l.So You get a 0.381 M NaCl.
