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First calculate the mass you need from NaCl I will calculate it for you now: 100 cm3= 0,100 L n (NaCl) = 0,1 mol/dm3 * 0,100 L = 0,01 mol m (NaCl) = n*Mm = 0,01 mol * ( 22,99+35,45) g/mol = 0,01 mol * 58,44 g/mol = 0,5844 g You will need 0,5844 g NaCl and you will mix it woth 100 cm3 water
What else can I help you with?
How do you prepare a solution 2 percent NaCl wv?
To prepare a 2% NaCl (w/v) solution, you would dissolve 2 grams of NaCl in enough water to make 100 mL of solution. This means you would add 2 grams of NaCl to a flask and then add water until the total volume reaches 100 mL.
Which is more concentrated -20g of alkali in 250 cm3 of solution or 10 g of the same alkai in 500 cm3 of solution?
To determine which solution is more concentrated, we need to calculate the concentration of each solution in grams per cubic centimeter (g/cm3). For the first solution with 20g of alkali in 250 cm3 of solution, the concentration would be 20g / 250 cm3 = 0.08 g/cm3. For the second solution with 10g of alkali in 500 cm3 of solution, the concentration would be 10g / 500 cm3 = 0.02 g/cm3. Therefore, the first solution with 20g of alkali in 250 cm3 of solution is more concentrated at 0.08 g/cm3 compared to the second solution with 10g of alkali in 500 cm3 of solution at 0.02 g/cm3.
How would you make 100cm3 of 0 01 mol dm3 copper sulfate from a solution of 0 1 mol dm3 copper sulfate?
right i dont know this 4 sure but because u want a 0.1 mol/dm3 and u only need 100cm3 u will need 0.01mols of copper sulfate to dilute in 100cm3. soo now u have a solution that is 0.01mols per 100cm3 or 0.1 mols per 1000cm3 (dm3)
What is the volume of 100g of water in cm3?
The number of grams is the number of cm3. e.g. 300g = 300cm3
When table salt sodium chloride (NaCl) is placed in water?
Because its molecules (sodium bound ionically to chlorine) can spread out within the water (H2O) molecules. The polar water molecules attract both the sodium (positive ions) and the chlorine (negative ions). You may be interested to know that you can dissolve 34 grams of salt in 100 cm3 of water at 10 degrees C.
How do you prepare a solution 2 percent NaCl wv?
To prepare a 2% NaCl (w/v) solution, you would dissolve 2 grams of NaCl in enough water to make 100 mL of solution. This means you would add 2 grams of NaCl to a flask and then add water until the total volume reaches 100 mL.
What is the density of the 10 percent NaCl solution is?
This density is 1,0707 g/cm3 at 20 0C.
What two physical properties of salt water?
- freezing point for a solution of 35 g/L NaCl: -2 deg. Celsius- density for a solution of 35 g/L NaCl: 1,025 g/cm3- thermal conductivity for a solution of 35 g/L NaCl: 0,6 W/m.K
What are two physical properties of salt water?
- freezing point for a solution of 35 g/L NaCl: -2 deg. Celsius- density for a solution of 35 g/L NaCl: 1,025 g/cm3- thermal conductivity for a solution of 35 g/L NaCl: 0,6 W/m.K
What mass of sodium chloride will be required to prepare 100 cm3 of 0.0282 M of sodium chloride?
The answer is 0,1648 g NaCl.
How do you make up a solution of phenolphthalein from a whit solid of phenolphthalein?
Dissolve 0.1g of the powder in ethanol and dilute with distilled water upto 100 cm3
Which is more concentrated -20g of alkali in 250 cm3 of solution or 10 g of the same alkai in 500 cm3 of solution?
To determine which solution is more concentrated, we need to calculate the concentration of each solution in grams per cubic centimeter (g/cm3). For the first solution with 20g of alkali in 250 cm3 of solution, the concentration would be 20g / 250 cm3 = 0.08 g/cm3. For the second solution with 10g of alkali in 500 cm3 of solution, the concentration would be 10g / 500 cm3 = 0.02 g/cm3. Therefore, the first solution with 20g of alkali in 250 cm3 of solution is more concentrated at 0.08 g/cm3 compared to the second solution with 10g of alkali in 500 cm3 of solution at 0.02 g/cm3.
Molarity of 0.20 g percent NaCl?
The density of sodium chloride is 2,165 g/cm3.
Density and melting point of NaCl?
The sodium chloride density is 2,165 g/cm3 and the melting point is 801 0C.
How many cm3 are in 10 m3?
1 m = 100 cm So 1 m3 = 100*100*100 cm3 = 106 cm3 and 10 m3 = 107 cm3
How many moles of NaCl are contained in 27.5 mL of 0.105M NaCl solution?
volume given =27.5mlmolarity of base=0.105find number of moles=moles=vol(cm3)/1000*molarity of NaClmoles=27.5/1000*0.105=3.82 moles of sodium chloride
2.943g of pure sulphuric acid H2S4 is dissolved in water to make 150.0 cm3 of solution What is the concentration of the solution?
The concentration of a solution is moles/volume. 2.943g of pure sulphuric acid H2S4 is approximately 15 moles, and 15/150 cm3 is 10.
