Dissolve 10 g anhydrous iron(III) chloride in distilled water.
To prepare a solution of 10% FeCl3, you would weigh out 10 grams of FeCl3 and dissolve it in enough water to make a total volume of 100 mL. Remember to always wear appropriate personal protective equipment when working with chemicals.
The molar mass of FeCl3 is 162.20 g/mol. First, convert 40.0 g to moles by dividing by the molar mass. Then, calculate the concentration in mol/L by dividing the moles of FeCl3 by the volume of the solution in liters (0.275 L).
The amount of FeCl3 needed depends on the concentration of the FeCl3 solution required for the test. Typically, a 2-5% solution of FeCl3 is used. To make a 100mL of 2-5% FeCl3 solution, you would need to dissolve 2-5 grams of FeCl3 in distilled water. The exact amount can be calculated using the formula: (desired % concentration/100) x volume of solution needed x molar mass of FeCl3.
To find the moles of Fe2S3 produced, convert 0.690 g to moles using the molar mass of Fe2S3. Then, use the stoichiometry of the reaction to determine the moles of FeCl3 required. Finally, use the molarity of FeCl3 to calculate the volume in milliliters needed, keeping in mind the percent yield.
FeCl3 + H2O4-2 +Zn
To prepare a solution of 10% FeCl3, you would weigh out 10 grams of FeCl3 and dissolve it in enough water to make a total volume of 100 mL. Remember to always wear appropriate personal protective equipment when working with chemicals.
.2M x V FeCl3=moles FeCl3 x 1mole Fe2S3/2mole FeCl3=moles of Fe2S3 x mm of Fe2S3/1 mole Fe2S3= g Fe2S3 x .65% yield. 2.75g Fe2S3/ .65= 4.23g Fe2S3/ 207.91= .02035 x 2mole FeCl3=.0407 moles FeCl3/ .2M FeCl3= .2035 L x 1000= 203.5 ml
Many people think that the gram is a measurement of volume. However, the gram is a measurement of weight, and so 100 grams weighs 100 grams or 3.52739619 ounces.Water weighs 8.34 (rounded to the nearest hundredth) pounds. 900 millilitres is equal to 0.237754846 US gallons. Therefore, 900 millilitres of water weighs about 1.98287542 pounds or 899.417161 grams.
The molar mass of FeCl3 is 162.20 g/mol. First, convert 40.0 g to moles by dividing by the molar mass. Then, calculate the concentration in mol/L by dividing the moles of FeCl3 by the volume of the solution in liters (0.275 L).
The amount of FeCl3 needed depends on the concentration of the FeCl3 solution required for the test. Typically, a 2-5% solution of FeCl3 is used. To make a 100mL of 2-5% FeCl3 solution, you would need to dissolve 2-5 grams of FeCl3 in distilled water. The exact amount can be calculated using the formula: (desired % concentration/100) x volume of solution needed x molar mass of FeCl3.
To make a fraction from any percent, divide the percent by 100. 10 percent = 10/100 or 1/10 .
To make a decimal into a percent, just multiply by 100. 0.1*100 is 10. 0.1 is 10 percent.
Iron chlorides are FeCl2 and FeCl3.
To find the moles of Fe2S3 produced, convert 0.690 g to moles using the molar mass of Fe2S3. Then, use the stoichiometry of the reaction to determine the moles of FeCl3 required. Finally, use the molarity of FeCl3 to calculate the volume in milliliters needed, keeping in mind the percent yield.
FeCl3 + H2O4-2 +Zn
To find the number of moles in 1.1 grams of FeCl3, you'll first determine the molar mass of FeCl3 (55.85 + 35.45*3) = 162.31 g/mol. Then, divide the given mass (1.1g) by the molar mass to get the number of moles (1.1g / 162.31g/mol ≈ 0.007 moles of FeCl3).
I don't have a good calculator, but i'll talk you through (will actually benefit you to do it yourself, this will come back to bite you if you don't learn it). Avagadros number is no. molecules per mole. 5.88x1028 / avagadros number gives your amount of moles. Moles / molecular weight gives weight