add 50% water to it
To make a 1% HCl solution from a 35% HCl solution, you would need to dilute the concentrated solution with water. The ratio of concentrated HCl to water would be approximately 1:34. So, to make 1% HCl, you would mix 1 part of the 35% HCl solution with 34 parts of water.
To make 0.5 N HCl solution, you can mix 1 part of concentrated HCl (approximately 11.6 M) with 23 parts of water. For example, you could mix 50 ml of concentrated HCl with 1150 ml of water to make 1200 ml of 0.5 N HCl solution. Always remember to add acid to water slowly to avoid splattering.
To find the moles of HCl, first calculate the millimoles of HCl in 50 mL: 4.0 mol/L * 50 mL = 200 mmol. Then convert millimoles to moles by dividing by 1000: 200 mmol / 1000 = 0.2 moles of HCl. Therefore, there are 0.2 moles of HCl in 50 mL of 4.0 M HCl.
To make 0.6M HCl (hydrochloric acid), you would need to dilute a more concentrated solution of hydrochloric acid with water to achieve the desired molarity. For example, to make 1 liter of 0.6M HCl from concentrated 12M HCl, you would need to mix approximately 50 mL of 12M HCl with 950 mL of water. It is essential to add the acid to water slowly while stirring to prevent splashing and ensure safety.
44.5 ml HCl TAKE AND DILUTE UP TO 1000 ML WATER MAKE A 0.5 M HCl SOLUTION
To make a 1% HCl solution from a 35% HCl solution, you would need to dilute the concentrated solution with water. The ratio of concentrated HCl to water would be approximately 1:34. So, to make 1% HCl, you would mix 1 part of the 35% HCl solution with 34 parts of water.
No
50% = 1/2
To make 0.5 N HCl solution, you can mix 1 part of concentrated HCl (approximately 11.6 M) with 23 parts of water. For example, you could mix 50 ml of concentrated HCl with 1150 ml of water to make 1200 ml of 0.5 N HCl solution. Always remember to add acid to water slowly to avoid splattering.
To find the moles of HCl, first calculate the millimoles of HCl in 50 mL: 4.0 mol/L * 50 mL = 200 mmol. Then convert millimoles to moles by dividing by 1000: 200 mmol / 1000 = 0.2 moles of HCl. Therefore, there are 0.2 moles of HCl in 50 mL of 4.0 M HCl.
Let A be the volume of 33% HCl and B the volume of 20% HCl Then, A + B = 5.........so, B = 5 - A And, 33A + 20B = 5 x 30.5 = 152.5 Substituting for B gives :- 33A + 20(5 - A) = 33A + 100 - 20A = 13A + 100 = 152.5 Thus, 13A = 152.5 - 100 = 52.5 : A = 52.5/13 = 4.0385 Litres (4dp) Which means that B = 5 - 4.0385 = 0.9615 Litres Mix 4.0385 Litres of 33% HCL with 0.9615 Litres of20% HCl to get 5 litres of 30.5% HCl.
nope 50 percent.
50 ml
i dont knw
0.084%
120liters
To make 0.6M HCl (hydrochloric acid), you would need to dilute a more concentrated solution of hydrochloric acid with water to achieve the desired molarity. For example, to make 1 liter of 0.6M HCl from concentrated 12M HCl, you would need to mix approximately 50 mL of 12M HCl with 950 mL of water. It is essential to add the acid to water slowly while stirring to prevent splashing and ensure safety.