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To prepare 0.2N ferrous ammonium sulfate, you would weigh out the appropriate amount of ferrous ammonium sulfate hexahydrate based on its molecular weight, dissolve it in distilled water, and then dilute the solution to the desired volume. Finally, check and adjust the concentration if needed by titration or dilution.
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What is the value of a Bank of England Five Pound note Chief Cashier J B Page serial number 02N 808670?
A Bank of England Five Pound note (Series D - blue)(Chief Cashier J.B. Page - serial 02N), uncirculated and in absolute mint condition could fetch anything from £5 up to £30 GBP. If it has been circulated but still in good condition, it might fetch anything from £8 to £15 GBP. A reputable coin dealer will be able to give a more accurate valuation.
What are the coordinates of France?
Latidude of mainland France (including Corsica) from 51
What is the latitude of southern tip of Texas?
The latitude at the southernmost point in the lower Rio Grande Valley,about 7.7 miles southeast of the International Blvd. Bridge in Brownsville,is 25.8373 degrees north latitude.That's about 1,785 miles (2,870 km) north of the equator.
If an electron in a hydrogen atom relaxes to the second energy level emitting a photon of wavelength 410.2 nm what higher energy level did it start at?
There are actually two ways to do this. I'll explain how to use Rydberg's formula, though, because it's significantly simpler to use. Rydberg's Formula states: 1/(wavelength)=R (1/n1^2-1/n2^2) R= 1.097x10^7m^-1 (this is Rydberg's constant so you can look this up) n1=nfinal (or n=2 in this problem) n2=ninitial (what we are looking to find) wavelength=lambda=3.97x10^-7m Set up the problem: 1/3.97x10^-7m=(1.097x10^7m^-1)*(1/2^2-1/n^2) .2296=1/4-1/n^2 1=.02n^2 n^2=50 n=~7 Alternatively you could have used Bohr's model but that would take two formulas and a lot more work for the same answer (using Bohr's model is simply working backwards from what it is typically used for).
