Exactly how you prepare will depend on what you are starting with. Typically to make a 1 M HCl solution, you will be starting with a stock solution of more concentrated HCl that you will then dilute.
See the Related Questions for complete instructions on how to prepare a solution by diluting a stock solution.
1M HCl Solution*Concentrated HCl. its 37.5%.
*The density of concentrated HCl is 1.189g/ml we will need this number as well, and of course the Atomic Mass of HCl 36.46
* Calculation=((37.5/100)(1000)(1.189))/36.46 = 12.2M
*If HCl concentrated is 12.2 M then to make a 1L solution of 1M HCL
(12.2) x = 1(1)
x = 1(1)/(12.2)
x=0.082ml/ml of water
x = 82mL HCl per liter
How to prepare 2M HCl solution from con HCl
10N HCl is equivalent to 10 M HCl and the solution will contain 10 moles of HCl per 1 liter or solution. Depending on the volume of solution, the preparation will vary. To prepare 1 liter, place 360.5 g of HCl in a total volume of 1 L. To prepare 1 L from concentrate HCl (12.1 M) dilute 833 ml of conc. HCl to 1 L.
one mole of HCl in one litre of water, result in 1M HCl
0.25 N HCl is the same as 0.25 M HCl which is 0.25 moles HCl/liter of solution.
50ml
How to prepare 2M HCl solution from con HCl
10N HCl is equivalent to 10 M HCl and the solution will contain 10 moles of HCl per 1 liter or solution. Depending on the volume of solution, the preparation will vary. To prepare 1 liter, place 360.5 g of HCl in a total volume of 1 L. To prepare 1 L from concentrate HCl (12.1 M) dilute 833 ml of conc. HCl to 1 L.
one mole of HCl in one litre of water, result in 1M HCl
Prepare HCl 1 M by HCl concentration 37 % HCl concentration 37 % have density =1.19 g/ml HCl 1 M use HCl 37 % 82.81 ml make volume with water to 1 liter
0.25 N HCl is the same as 0.25 M HCl which is 0.25 moles HCl/liter of solution.
50ml
8.3ml HCl from 37% v/v stock bottle is required to prepare 0.1 M HCl solution.(answered by Prof.WASEEM UR RAHMAN KHAN)
Look at the bottle of HCl. It gives a molarity. then dilute to 0.25 M.
dilute your HCl solution to 0.2 M HCl solution and then follow above mentioned link : http://delloyd.50megs.com/moreinfo/buffers2.html
You're going to dilute the 1 M HCl in water to get a less concentrated 0.25 M HCl. First determine the amount of moles in the final 10 mL 0.25 M HCl. 10 mL = .01 L × .25 moles/L = .0025 moles HCl Now you work backwards with the concentrated solution. 1 mol/L × (volume) = .0025 moles HCl Volume = .0025 liters = 2.5 mL You need to prepare a 10 mL aqueous solution containing 2.5 mL of 1 M HCl.
you are not mentioned the desired volume.for example you want to prepare 0.25 M HCl in 100 ml. To make a 0.25 M solution, slowly add 2.207 mL of your stock (HCl) solution to 25 mL deionized water. Adjust the final volume of solution to 100 mL with deionized water.
To prepare a 5M HCl solution, you need to know the concentration of your source of HCl. Then you can use this proportion C1V1=C2V2, where C=Concentration in M(moles/liter) and V=Volume(liters).