answersLogoWhite

0

Iron(III) sulfide decomposes into iron(III) oxide and sulfur dioxide when heated. This can be visually demonstrated by heating a sample of iron(III) sulfide in a test tube and observing the formation of a reddish-brown residue (iron(III) oxide) and the release of a colorless gas (sulfur dioxide), which may be detected by its pungent odor.

User Avatar

AnswerBot

1y ago

What else can I help you with?

Related Questions

What is the formula for ironIII sulfide?

Fe2(SO3)2 I don't think the above answer is right...I believe it is Fe2S3


What is the decomposing chemical compound in the egg that is the source of the rotten smell?

The smell is from hydrogen sulfide - H2S.


Is ironIII bromide?

FeBr3


What is the compound formula of ironIII oxide?

Fe2O3


What is the chemical formula for IronIII Bromide?

Formula: FeBr3


How many moles of ironIII hydroxide are needed to react with excess nitric acid to produce 63.8 g ironIII nitrate?

Balanced equation. Fe(OH)3 + 3HNO3 --> Fe(NO3)3 + 3H2O 63.8 grams Fe(NO3)3 (1 mole Fe(NO3)3/241.88 grams)(1 mole Fe(OH)3/1 mole Fe(NO3)3 = 0.264 moles iron III hydroxide needed ==========================


What is the oxidation number of ironIII?

Iron(iii) ion = +3


Is ironIII a cation?

Yes it is and is also called ferric cation


If someone does drugs in their body is decomposing for three weeks will the drug show up?

Yes.


What is the chemical formula for ironIII acetate?

Formula: Fe(CH3COO)3


What is Chemical formula for ironIII hydroxide?

Formula: Fe(OH)3


Identify the number of moles of excess reagent left over when 4.821 moles of ironIII oxide are reacted with 5.591 moles of aluminum in the thermite reaction?

The balanced equation for the thermite reaction is: 2Al + Fe2O3 -> Al2O3 + 2Fe. This means that 2 moles of aluminum react with 1 mole of ironIII oxide. Therefore, if 5.591 moles of aluminum are used, 2.7955 moles of ironIII oxide will react. Since 4.821 moles of ironIII oxide are provided, the excess reagent is aluminum. The amount of excess aluminum left over is 5.591 moles - 2.7955 moles = 2.7955 moles.