How do you write an equation that shows the formation of a copperII ion from a neutral copper atom?

Answer 1

Copper(II) oxide is CuO. When binary compounds (compounds composed of only two elements) decompose, they produce their elements. So the unbalanced equation would be: CuO(s) --> Cu(s) + O2(g) Now you have 1 Cu and 1 O on the reactant side and 1 Cu and 2 O on the product side. To balance, first put a coefficient of 2 in front of CuO so each side has 2 O. 2CuO(s) --> Cu(s) + O2(g) This leaves 2 Cu on the reactant side, but only 1 Cu on the product side so now put a coefficient of 2 in front of Cu so each side has 2 Cu. 2CuO(s) --> 2Cu(s) + O2(g) The equation is balanced!

Answer 2

Correct answer:

Your response:

+

Correct answer:

Cu

Cu

Your response:

Cu

Correct answer:

Cu2+

Cu^2+^

Your response:

Cu2+

+

Correct answer:

2 e-

2 e^-^

Your response:

e-

Answer 3

Metallic copper reacts with an excess of oxygen to form copper(II) oxide or with a deficiency of oxygen to form copper(I) oxide.

Answer 4

The equation would be: Cu(s) + 2e- -> Cu2+(aq). This shows the neutral copper atom losing 2 electrons to form the copper(II) ion in aqueous solution.