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∙ 12y agoCopper(II) oxide is CuO. When binary compounds (compounds composed of only two elements) decompose, they produce their elements. So the unbalanced equation would be: CuO(s) --> Cu(s) + O2(g) Now you have 1 Cu and 1 O on the reactant side and 1 Cu and 2 O on the product side. To balance, first put a coefficient of 2 in front of CuO so each side has 2 O. 2CuO(s) --> Cu(s) + O2(g) This leaves 2 Cu on the reactant side, but only 1 Cu on the product side so now put a coefficient of 2 in front of Cu so each side has 2 Cu. 2CuO(s) --> 2Cu(s) + O2(g) The equation is balanced!
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∙ 15y agoWiki User
∙ 12y agoCorrect answer:
Your response:
+
Correct answer:
Cu
Cu
Your response:
Cu
Correct answer:
Cu2+
Cu^2+^
Your response:
Cu2+
+
Correct answer:
2 e-
2 e^-^
Your response:
e-
The equation would be: Cu(s) + 2e- -> Cu2+(aq). This shows the neutral copper atom losing 2 electrons to form the copper(II) ion in aqueous solution.
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∙ 14y agoMetallic copper reacts with an excess of oxygen to form copper(II) oxide or with a deficiency of oxygen to form copper(I) oxide.
The symbol equation for the formation of copper sulphide is: Cu(s) + S(s) → CuS(s)
The ionic equation for the reduction of copper sulfate (CuSO4) to copper oxide is: Cu^2+ + 2e^- → Cu This equation represents the reduction half-reaction where copper ions (Cu^2+) gain two electrons to form solid copper (Cu). The formation of copper oxide involves further reactions and would require a more comprehensive equation.
The oxidation number of copper (II) is +2. This means that copper has lost two electrons in a chemical reaction and has a charge of +2.
The chemical equation is:Zn + CuSO4 = ZnSO4 + Cu
The given equation is a balanced chemical equation representing a single replacement reaction, where zinc (Zn) replaces copper (Cu) in the copper sulfate (CuSO4) solution. This reaction results in the formation of zinc sulfate (ZnSO4) and solid copper (Cu).
The chemical formula (not equation) of copper(II) chloride is CuCl2.
No copper (II) chloride is an ionic compound.
Copper(II) oxide is CuO; II is an indication that in this compound copper is bivalent.
Copper(II) sulfate has the formula CuSO4.
Copper(II) chloride is already a compound; its formula is CuCl2
The symbol equation for the formation of copper sulphide is: Cu(s) + S(s) → CuS(s)
The ionic equation for the reduction of copper sulfate (CuSO4) to copper oxide is: Cu^2+ + 2e^- → Cu This equation represents the reduction half-reaction where copper ions (Cu^2+) gain two electrons to form solid copper (Cu). The formation of copper oxide involves further reactions and would require a more comprehensive equation.
The oxidation number of copper (II) is +2. This means that copper has lost two electrons in a chemical reaction and has a charge of +2.
31.3 g CuO
The chemical equation is:Zn + CuSO4 = ZnSO4 + Cu
The given equation is a balanced chemical equation representing a single replacement reaction, where zinc (Zn) replaces copper (Cu) in the copper sulfate (CuSO4) solution. This reaction results in the formation of zinc sulfate (ZnSO4) and solid copper (Cu).
The complete ionic equation for the reaction between copper(II) sulfate and barium chloride is: Cu^2+(aq) + SO4^2-(aq) + 2Ba^2+(aq) + 2Cl^-(aq) → BaSO4(s) + CuCl2(aq)