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What is the ionic equation of cacl2 plus na2s equals cas plus nacl?
The balanced molecular equation is CaCl2 + Na2S -> CaS + 2NaCl. To write the ionic equation, we need to break down the reactants and products into their respective ions. This results in the ionic equation: Ca2+ + 2Cl- + 2Na+ + S2- -> CaS + 2Na+ + 2Cl-. Cross out spectator ions that appear on both sides of the equation to obtain the net ionic equation: Ca2+ + S2- -> CaS.
What net ionic equation describes the reaction when these solutions are mixed?
To determine the net ionic equation, write out the balanced molecular equation first. Then, write the complete ionic equation with all ions separated. Finally, cancel out spectator ions (ions that appear on both sides of the equation) to arrive at the net ionic equation, which shows only the reacting ions.
How is a net ionic equation written from a ionic equation?
the spectator ions are removed
How is a net ionic equation written in a complete ionic equation?
To write a net ionic equation from a complete ionic equation, you remove the spectator ions that appear on both sides of the equation. The remaining ions that participate in the reaction are then included in the net ionic equation. This simplifies the equation to show only the ions that undergo a chemical change.
How do you write an ionic equation?
To write an ionic equation, first write the balanced chemical equation for the reaction. Then, separate the soluble ionic compounds into their respective ions. Finally, eliminate the spectator ions that do not participate in the reaction to form the net ionic equation.
What is the ionic equation of cacl2 plus na2s equals cas plus nacl?
The balanced molecular equation is CaCl2 + Na2S -> CaS + 2NaCl. To write the ionic equation, we need to break down the reactants and products into their respective ions. This results in the ionic equation: Ca2+ + 2Cl- + 2Na+ + S2- -> CaS + 2Na+ + 2Cl-. Cross out spectator ions that appear on both sides of the equation to obtain the net ionic equation: Ca2+ + S2- -> CaS.
What is the molecular equation of CuNO32and NaS2?
For the molecular balance of the equation it would be: CuSO4 (aq) + Na2S (aq) = CuS (s) + Na2SO4 (aq). For the net ionic balance of the equation it would be: Cu2+ (aq) + S2(aq) = CuS (s).
What net ionic equation describes the reaction when these solutions are mixed?
To determine the net ionic equation, write out the balanced molecular equation first. Then, write the complete ionic equation with all ions separated. Finally, cancel out spectator ions (ions that appear on both sides of the equation) to arrive at the net ionic equation, which shows only the reacting ions.
How is a net ionic equation written from a ionic equation?
the spectator ions are removed
How is a net ionic equation written in a complete ionic equation?
To write a net ionic equation from a complete ionic equation, you remove the spectator ions that appear on both sides of the equation. The remaining ions that participate in the reaction are then included in the net ionic equation. This simplifies the equation to show only the ions that undergo a chemical change.
How do you write an ionic equation?
To write an ionic equation, first write the balanced chemical equation for the reaction. Then, separate the soluble ionic compounds into their respective ions. Finally, eliminate the spectator ions that do not participate in the reaction to form the net ionic equation.
How do you write a total ionic equation and a molecular equation from a net equation The net is the only one supplied. i have to come up with the other two. im lost?
To write a total ionic equation from a net ionic equation, start by breaking down the compounds into their respective ions (if they are ionic compounds) and including only the ions that participate in the reaction. To write a molecular equation, simply write out the complete chemical equation including all reactants and products without breaking them down into ions. Remember, a net ionic equation shows only the ions that participate in the reaction, whereas a total ionic equation includes all ions involved.
How do I enter the net ionic equation for the reaction of aqueous sodium chloride with aqueous silver nitrate?
The reaction between sodium chloride (NaCl) and silver nitrate (AgNO3) results in the formation of silver chloride (AgCl) which is insoluble. Thus, the net ionic equation isAg^+(aq) + Cl^-(aq) ==> AgCl(s)
How to wrote the Net ionic equation of NaOH plus H2C4H4O6?
To write the net ionic equation for NaOH + H2C4H4O6, first write the balanced molecular equation: NaOH + H2C4H4O6 -> NaC4H4O6 + H2O. Then, split the compounds into ions and remove spectator ions: Na+ + OH- + H2C4H4O6 -> Na+ + C4H4O6^2- + H2O. The net ionic equation is OH- + H2C4H4O6 -> C4H4O6^2- + H2O.
What is the equation of net benefit?
The equation for net benefit is: Net Benefit = Total Benefit - Total Cost
Write the net ionic equation of the reaction BaCl2 with Na2CO3?
BaCl2 + Na2CO3 -> BaCO3 + 2NaCl
How do you write a net ionic equation for FeCl2 and MnO3?
I suppose that MnO3 doesn't exist; you think probable to Mn2O3.
