Copper(II) nitrate (Cu(NO3)2) reacts with tin (Sn) to form tin(II) nitrate (Sn(NO3)2) and copper metal (Cu) according to the equation: Cu(NO3)2 + Sn -> Sn(NO3)2 + Cu
Cu(NO3)2 and CuNO3 cupric (Cu-II) and cuprous (Cu-I) nitrate
One mole of anhydrous Cu(NO3)2 has 187,5558 g.
If the reaction includes copper (II): Cu + 2AgNO3 yields 2Ag + Cu(NO3)2 If the reaction includes copper (I): Cu + AgNO3 yields Ag + Cu(NO3) Then spectator ions are dis regarded: 2Ag[ion] + Cu[metal] --> 2Ag[metal] + Cu[2+ ion]
The balanced chemical equation for the reaction between magnesium and copper(II) nitrate is: Mg + Cu(NO3)2 -> Mg(NO3)2 + Cu
Cu(NO3)2 is the chemical formula for Copper II Nitrate.
When 3 moles Cu react 3 moles of copper nitrate are obtained.
The answer is 3 moles of Cu)NO3)2..
It generally refers to Copper(II) nitrate: Cu(NO3)2
Cu(NO3)2 and CuNO3 cupric (Cu-II) and cuprous (Cu-I) nitrate
Cu + HNO3 = Cu(NO3)2 + NO + H2O
One mole of anhydrous Cu(NO3)2 has 187,5558 g.
The formula for aqueous copper nitrate is Cu(NO3)2.
If the reaction includes copper (II): Cu + 2AgNO3 yields 2Ag + Cu(NO3)2 If the reaction includes copper (I): Cu + AgNO3 yields Ag + Cu(NO3) Then spectator ions are dis regarded: 2Ag[ion] + Cu[metal] --> 2Ag[metal] + Cu[2+ ion]
Fe + Cu(NO3)2 --> Fe(No3)2 + Cu
The chemical formula of stannous nitrate is Sn(NO3)2.
The balanced chemical equation for the reaction between magnesium and copper(II) nitrate is: Mg + Cu(NO3)2 -> Mg(NO3)2 + Cu
Formulas are: Sn(NO3)2 and Sn(NO3)4.