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It forms a divalent cation, Ca2+, by losing two electrons and attains the electronic configuration of [Ar].

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How does neon obey the octet rule when reacting to form ionic compounds?

Neon does not typically form ionic compounds because it already has a full valence shell with 8 electrons, satisfying the octet rule. Its electron configuration (1s^2 2s^2 2p^6) makes it very stable and unreactive with other elements.


How does calcium obey the octet rule when reating to form compounds?

Calcium is a group 2 element and typically loses 2 electrons to achieve a stable electron configuration with a full outer shell. By losing these 2 electrons, calcium is able to achieve an octet configuration in its outermost shell, similar to the noble gas configuration.


Will any of the chlorine oxides obey the octet rule?

No chlorine oxides will obey the octet rule.


What molecules does not obey the octet rule?

BF3 and other Lewis acids. Also BrF5 and other inter-halogen compounds.


Does AmH3 obeys the octect rule?

No, Transition metals do not obey the octet rule in simple compounds , Am is an 'f' block transition metal.


How does sodium obey the octet rule when reacting to form compounds?

Sodium typically loses its one valence electron to achieve a stable electron configuration, resembling the nearest noble gas (Neon), thereby obeying the octet rule. This electron loss allows sodium to form a stable ionic bond with other elements by attaining a complete outer shell with 8 electrons.


In which bonding patterns does X obey the octet rule?

no it does not follow octet rule


How do covalent compounds obey the octet rule?

Covalent compounds obey the octet rule by sharing electrons between atoms in order to achieve a full outer shell of electrons, usually 8 electrons. This sharing allows each atom to achieve greater stability by filling its valence shell with the desired number of electrons.


What do not obey the octet rule cs2 ci4 no3 po43 sci4?

Cs2, NO3, and PO43 do not obey the octet rule because they have an odd number of valence electrons. CI4 and SCI4 do not obey the octet rule because the central atom (Cl or S) exceeds the octet by having more than eight valence electrons.


How does oxygen obey the octect rule when reacting to form compounds?

more than sure that whole group is covalent bonding such as Iodine is written I2 or Bromine is Br2. Fluorine is also in this, example F2, the 2 outer electrons as each is 19, 2,8,8,1 is shared between the 2 atoms.


How does calcium obey the octet rule when reacting to form compound?

Calcium will generally bond to 2 halide atoms to attain a full outter shell. Calcium has 2 electrons already and can share with a halide like bromine to form CaBr2 . it may also combine with something like oxygen that has 6 electrons again giving a stable 8 electron complex CaO.


How many covalent bonds would the element tellurium be expected to form in order to obey the octet rule?

2