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The outermost (3rd) shell of aluminium is occupied with 3 electrons will gave away 3 electron away as it forms an ion, hence the outermost shell which was occupied by those 3 electrons gone, thus the size of aluminium atom decrease.

Added:

Above that there are 13 proton charges (3 extra) to attract more the remaining 10 electrons, so they'll stay closer to the nucleus.

Hence all positively charged ions are smaller than their respective neutral atoms.

The reversed is true for negative ions: Chloride (Cl-) is bigger compared to Chlorine.

(For spelling issue on aluminIUm i.s.o. aluminUm cf. Discussion-page)

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Q: How does the size of an aluminum atom change when it becomes an ion with a charge of 3 plus?
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