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Aqueous solution of SnCl2 is acidic?
Yes, the hydrolysis of salt produce the strong acid HCl along with weak base Sn(OH)2 SnCl2 + 2H2O = Sn(OH)2 + 2HCl
How many moles of ions are produced when 2 mol of Na2CO3 dissociate?
Na2CO32 * 2 = 4 moles sodium.===========================
How many mol of Ca2 plus ions are in 2.8 mol of Ca3N2?
2.8 moles Ca3N2 (3 mole Ca 2+/1 mole Ca3N2) = 8.4 moles Ca 2+ =============
Calculate the number of hydroxide ions present in 0.250 mol of Ca(OH)2?
Since there are 2 hydroxide ions (OH-) for every one molecule of Ca(OH)2, in 0.250 mol of Ca(OH)2 there are 0.500 mol of hydroxide ions. We can then multiply 0.500 mol by Avogadro's number to find the number of hydroxide ions present, which is approximately 3.01 x 10^23 ions.
How many moles of ions are released when 0.27 mol CoCl2 is dissolved in water?
Each molecule CoCl2 ionises in three single ions (1 Co2+ and 2 Cl- ions), so 0.27 mol CoCl2 gives 3 * 0.27 = 0.81 mole ions (0.27 mole Co2+ and 0.54 mole Cl- ions)
When you have 0.43 mol of NH4Cl how many total moles of ions are released when each of the following samples dissolves completely in water Show work so I can understand how to do it on my own?
When NH4Cl dissolves in water, it dissociates into NH4+ and Cl- ions. Since NH4Cl produces one NH4+ ion and one Cl- ion, for 0.43 mol of NH4Cl, there will be a total of 0.43 mol of NH4+ ions and 0.43 mol of Cl- ions released. Total moles of ions = 0.43 mol NH4+ + 0.43 mol Cl- = 0.86 mol ions The total moles of ions released when 0.43 mol of NH4Cl dissolves in water is 0.86 mol.
Aqueous solution of SnCl2 is acidic?
Yes, the hydrolysis of salt produce the strong acid HCl along with weak base Sn(OH)2 SnCl2 + 2H2O = Sn(OH)2 + 2HCl
How many moles of ions are produced when 2 mol of Na2CO3 dissociate?
Na2CO32 * 2 = 4 moles sodium.===========================
How many Cl- ions are present in 2.00 mol of KCl?
There are 2.00 mol of KCl, which means there are 2.00 mol x 1 Cl- ion per KCl = 2.00 mol Cl- ions present in 2.00 mol of KCl.
What is the molar concentration of cl- ions in a 0.500 m alcl3 solution?
3 mol Cl- ions per mol AlCl3 , so 3 * 0.5 = 1.5 mol/L Cl-
What is the number of chlorine ions in 0.5mol of titanium 3 chloride?
Titanium (III) chloride has the formula TiCl3 and therefore contains three chloride ions per formula unit. The number of chloride ions in 0.5 mol is therefore (3/2) X Avogadro's Number or 9 X 1023, to the justified number of significant digits.
How many mol of Ca2 plus ions are in 2.8 mol of Ca3N2?
2.8 moles Ca3N2 (3 mole Ca 2+/1 mole Ca3N2) = 8.4 moles Ca 2+ =============
Calculate the number of hydroxide ions present in 0.250 mol of Ca(OH)2?
Since there are 2 hydroxide ions (OH-) for every one molecule of Ca(OH)2, in 0.250 mol of Ca(OH)2 there are 0.500 mol of hydroxide ions. We can then multiply 0.500 mol by Avogadro's number to find the number of hydroxide ions present, which is approximately 3.01 x 10^23 ions.
How many moles of ions are released when 0.27 mol CoCl2 is dissolved in water?
Each molecule CoCl2 ionises in three single ions (1 Co2+ and 2 Cl- ions), so 0.27 mol CoCl2 gives 3 * 0.27 = 0.81 mole ions (0.27 mole Co2+ and 0.54 mole Cl- ions)
Why sncl4 more covalent than sncl2?
SnCl4 is more covalent than SnCl2 primarily due to the higher oxidation state of tin in SnCl4, which leads to a greater polarization of the chloride ions. The Sn4+ ion has a stronger positive charge, attracting the electron cloud of the Cl- ions more significantly, enhancing covalent character. In contrast, SnCl2, with Sn2+, exhibits less polarization and therefore has a greater ionic character. This difference in charge and polarization explains the greater covalent nature of SnCl4 compared to SnCl2.
How many moles of ions are in the solutionCalcium chloride (CaCl2) is an ionic compound that dissociates in water. A chemist forms a solution by mixing 0.50 mol CaCl2 and 1.0 kg of water?
When CaCl2 dissociates in water, it forms three ions: one Ca2+ ion and two Cl- ions for each formula unit of CaCl2. Therefore, 0.50 mol of CaCl2 would yield 0.50 mol Ca2+ ions and 1.0 mol Cl- ions in solution, totaling 1.5 moles of ions.
How many moles of ions are in 1.5 mol of NaCl?
Based on the stoichiometry of NaCl, for every one mole of NaCl there is one mole of Na+ and one mole of Cl-. Therefore, there are 1.5 moles Na+ and 1.5 moles Cl-, totaling 3 moles of ions altogether
