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The compound alcl3 is formed by combining aluminum and chlorine gas. This is what forms aluminum chloride which is an inorganic compound.
Wiki User
∙ 9y ago
Wiki User
∙ 11y agoit is made up of aluminium and chloride
by neethu
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How many molecules of water are formed when the following equation is balanced Al2O3 plus HCl AlCl3 plus H2O?
3
Is AlCl3 a covalent or ionic compound?
Solid AlCl3 is ionic. Liquid and gaseous AlCl3 is present as a covalent dimer, Al2Cl6. At high temperatures the dimer dissociates to form the planar covalent monomer AlCl3.
What is pH 0.1M AlCl3?
- log(0.1 M AlCl3) = 1 pH =====
What is the name of the ionic compound AlCl3?
AlCl3 is the compound aluminum chloride.
The valency of aluminium is 3 and the valence of chlorine is -1 the formula for aluminium chloride is correctly written as?
The correct formula is AlCl3
What is the formula for ionic compound formed between chloride and al3?
aluminum cloride
What will happen when hydrochloric acid reacts with aluminum?
Aluminium trichloride (AlCl3) is formed and hydrogen is released.
What is the maximum mass of aluminum chloride that can be formed when reacting 22.0 of aluminum with 27.0 of chlorine?
This equation shows how much AlCl3 can be produced with 22.0g of Al. 22.0g Al x (1 mol Al/26.98g) x (2 mol AlCl3/2mol Al) x (133.34 g/1 mol AlCl3) = 108.66g AlCl3 This equation shows how much AlCl3 can be produced with 27.0g of Cl2. 27.0g Cl2 x (1 mol Cl2/70.91g) x (2mol AlCl3/3 mol Cl2) x (133.34g/1 mol AlCl3) = 33.87g AlCl3 This shows that chlorine is the limiting reactant. Only 33.87 grams of AlCl3 can be produced before the chlorine will run out. Using significant figures, the answer is 33.8g of AlCl3
What is the maximum mass of aluminium chloride that can be formed when reacting 27.0 of aluminum with 32.0 of chlorine?
The answer is 40.1 g AlCl3, assuming that the questioner meant 27.0 g and 32.0 g (the units weren't provided in the question). It was calculated as follows: 27.0 g of Al is 27.0 g/27.0 g/mol = 1.00 mol of Al. 32.0 g of Cl is 32.0 g/35.45 g/mol = 0.903 mol of Cl. Aluminium chloride has the molecular formula of AlCl3, therefore it takes three moles of chlorine to form one mole of aluminum chloride, or in this case, it would take 3.00 mol of Cl to react with 1.00 mol of Al. It is clear that the amount of AlCl3 that can be formed is limited by the moles of Cl available, specifically the maximum number of moles of AlCl3 that can be formed is 0.903 mol/3 = 0.301 mol. 0.301 mol AlCl3 is equivalent to: 0.301 mol AlCl3 x 133.35 g AlCl3/mol = 40.1 g AlCl3.
What is meant by anhydrous AlCl3?
anhydrous means without water and anhydrous AlCl3 means, AlCl3 is hydrated in water therefore anhydrous AlCl3 is used.
How many molecules of water are formed when the following equation is balanced Al2O3 plus HCl AlCl3 plus H2O?
3
Is alcl3 an electrolyte?
Yes, AlCl3 is a strong electrolyte.
Is CO SO2 AlCl3 or NO a nonpolar molecule?
AlCl3
What are the products when these react AlCl3 and HNO3 and AgNO3?
alcl3+hno3
When Al2O3 is heated what compound is produced?
AlCl3 & H2O AlCl3 & H2O Solving Al2O3 (s) in HCl Al2O3 (s) + 6 HCl (aq) → 2 [AlCl3] (s, aq*) + 3 H2O (l) *depending on amount of acid used. Excessive amounts of acid will solve the formed AlCl3 (s) into 2([Al3+][Cl-]3) (aq)
If 328 grams of aluminum hydroxide react with excess hydrochloric acid how many grams of aluminum chloride can be formed?
Balanced equation first. ( you have been told the limiting reactant. ) Al(OH)3 + 3HCl >> AlCl3 + 3H2O Molar mass Al(OH)3 = 78.004 grams/// Molar mass AlCl3 = 133.33 grams Conversion. 328g Al(OH)3 (1mol Al(OH)3/78.004g)(1 mol AlCl3/1mol Al(OH)3)(133.33g AlCl3/1mol AlCl3) =560.64 grams produced
How would the quantity of energy involved when LiCl is formed compare to the quantity of energy involved when AlCl subscript 3 is formed?
For LiCl: 408,6 kJ/mol. For AlCl3: 704,7 kJ/mol.
