M.W. of the given compound is 3x23+1x31+4x16=164
in Na3PO4 3 moles of Na+ ions are produces
i.e., 1mole weighs 164g contain 3x6.023x10^23 Na+ ions
?5.43g contain = 5.43g x 3 moles Na+ x 6.023x10^23 / 164 g/mol
Na+ ions=0.598x10^23
IT GIVES Na+(ion) and PO4-3 IONS WHEN DISSOVED IN WATER .
The molarity of Na+ ions in a 0.25 M solution of Na3PO4 is 0.75 M. This is because each formula unit of Na3PO4 dissociates into 3 Na+ ions in solution. Therefore, the concentration of Na+ ions is three times the molarity of the Na3PO4 solution.
The compound formed by Na+ and PO43- ions is sodium phosphate, which has the chemical formula Na3PO4.
The solubility product expression for sodium phosphate (Na3PO4) is Ksp = [Na+]^3[PO4]^-3, where [Na+] and [PO4]^- are the concentrations of sodium ions and phosphate ions, respectively, in the solution.
The chemical formula for sodium phosphate is Na3PO4, which exists as a solid white powder at room temperature
IT GIVES Na+(ion) and PO4-3 IONS WHEN DISSOVED IN WATER .
The molarity of Na+ ions in a 0.25 M solution of Na3PO4 is 0.75 M. This is because each formula unit of Na3PO4 dissociates into 3 Na+ ions in solution. Therefore, the concentration of Na+ ions is three times the molarity of the Na3PO4 solution.
There are 0.75 moles of sodium ions present in 2.50 L of 0.300 M Na3PO4. Each formula unit of Na3PO4 has 3 sodium ions. So, for every mole of Na3PO4, there are 3 moles of sodium ions. Calculating the moles of sodium ions: 2.5 L * 0.300 mol/L * 3 mol Na+ / 1 mol Na3PO4 = 0.75 moles of Na+.
The compound formed by Na+ and PO43- ions is sodium phosphate, which has the chemical formula Na3PO4.
The solubility product expression for sodium phosphate (Na3PO4) is Ksp = [Na+]^3[PO4]^-3, where [Na+] and [PO4]^- are the concentrations of sodium ions and phosphate ions, respectively, in the solution.
The chemical formula for sodium phosphate is Na3PO4, which exists as a solid white powder at room temperature
The ions that are present in the solution of sodium phosphate is the sodium ions and the phosphate ions. The sodium ion has +3 charge while the phosphate ion has the -3 charge.
When Na3PO4 dissociates in water, it breaks apart into its ions: 3 Na+ ions and 1 PO4^3- ion. This dissociation process occurs due to the strong attraction between the ions and the polar water molecules, which surround and stabilize the individual ions. The dissociation of Na3PO4 is a reversible chemical reaction, meaning that the ions can recombine to form the original compound under certain conditions.
Let us find moles first. Molarity = moles of solute/Liters of solution ( 750 ml = 0.750 Liters ) 0.375 M Na2SO4 = moles Na2SO4/0.750 Liters = 0.28125 moles Na2SO4 =================== 0.28125 moles Na2SO4 (142.05 grams/1 mole Na2SO4) = 39.95 grams Na2SO4 needed ---------------------------------------you do significant figures!
Na3PO4 is an ionic compound because it is made up of positively charged sodium ions (Na+) and negatively charged phosphate ions (PO4^3-), which are held together by electrostatic forces of attraction.
The concentration of Na+ in Na3PO4 is 0.090 M. This is because for every 1 mole of Na3PO4, there are 3 moles of Na+ ions. So in a 0.030 M solution of Na3PO4, the concentration of Na+ is 3 times that, which is 0.090 M.
The net ionic equation for Na3PO4 is 3Na+ + PO4^3- -> Na3PO4. This equation shows that the sodium ion (Na+) and phosphate ion (PO4^3-) combine to form sodium phosphate (Na3PO4) without any spectator ions.