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To find the number of atoms in 6.35 g of copper, you first need to determine the number of moles of copper present by dividing the mass of copper by its molar mass (63.55 g/mol). Then, you can use Avogadro's number (6.022 x 10^23 atoms/mol) to find the number of atoms in that number of moles.

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1y ago

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What is the atomic number of the copper atom?

63.54 g/mol


What is the mass in grams of atom of copper and how many atom are there 1g of copper?

6.022*10**23 atoms / mol = avagadro's constant 63.546 g / mol = atomic weight of copper 1 atom / 6.022*10**23 atoms/mol * 63.546 g/mol = 1.05523082*10**-22g 1 g / 63.546 g/mol * 6.022*10**23 atoms/mol = 9.476599629*10**21 atoms


A sample of copper with a mass of 63.5 g contains 6.02x1023 atoms calculate the mass of the single copper?

17.48 atoms


What is the mass of 9 atom(s) of copper in grams?

The atomic mass of copper is approximately 63.55 g/mol. Therefore, the mass of 9 atoms of copper would be 9 times the atomic mass, which is 9 * 63.55 g/mol. This equals 571.95 grams.


What is the diameter of a copper atom with atomic mass is 63.5 and density is 8.93ESP3 kgm-3?

The product of the units atomic mass (g/mol), Avogadro's number(mol/atom), 1/density (m^3/kg) and, 1(kg/g) yield the volume of a copper atom. (63.5*(1/6.022E23)/(8930*1000)= 1.12E-23m^3. The volume of a sphere is given as 4(pi)(r^3)/3. Solving for r: r=(3*1.12E-23/(4pi))^(1/3)=1.41E-10m. Multiplying by 2, d = 2.42E-10m.


How many protons in 3.18 gm of copper?

3.18 grams copper (1 mole Cu/63.55 grams)(6.022 X 10^23/1 mole Cu) = 3.01 X 10^22 atoms of copper there are 29 protons in one atom of copper, so............... 29 * 3.01 X 10^22 = 8.73 X 10^23 protons in 3.18 grams of copper


What is the volume in milliliters of a 9857-g ingot of copper?

The density of copper is 10.0 g/mL. What is the volume in milliliters of a 2184-g ingot of copper?


How many atoms are present in helium lithium beryllium boron carbon nitrogen and oxygen?

1 mole of the element has 6.023 x 1023 atoms 1 mole = 4 g of helium = 7 g of lithium = 9 g of beryllium = 11 g of boron = 12 g of carbon = 14 g of nitrogen = 16 g of oxygen


How many moles of oxygen atoms combine with 127 g of copper?

One mole of oxigen (O2-the diatomic molecule) is needed for 127,092 g copper to form CuO.


If you add 35 g of copper (II) sulfate CuSO4 to 100 g of water at 60 and degC according to the transparency how many grams of copper(II) sulfate will not dissolve HTML Editor Keyboard Shortcuts?

At 60°C, about 31.6 g of copper (II) sulfate will dissolve in 100 g of water. This means that about 3.4 g of copper (II) sulfate will not dissolve and will form a saturated solution.


How many grams of cadmium must react to displace 13.7 g of copper from a solution of copper nitrate?

Cd= 24.23718445g


If you have 1.20 and times 1024 atoms of copper how many moles of copper do you have?

To find the number of moles of copper, we first need to calculate the total mass of copper in the sample. Copper has an atomic mass of 63.55 g/mol. The total mass of the sample is 1.20 g x 1024 atoms = 1228.8 g. Next, we convert this mass to moles by dividing by the atomic mass of copper: 1228.8 g / 63.55 g/mol = 19.36 moles of copper.