To find the number of atoms in 6.35 g of copper, you first need to determine the number of moles of copper present by dividing the mass of copper by its molar mass (63.55 g/mol). Then, you can use Avogadro's number (6.022 x 10^23 atoms/mol) to find the number of atoms in that number of moles.
6.022*10**23 atoms / mol = avagadro's constant 63.546 g / mol = atomic weight of copper 1 atom / 6.022*10**23 atoms/mol * 63.546 g/mol = 1.05523082*10**-22g 1 g / 63.546 g/mol * 6.022*10**23 atoms/mol = 9.476599629*10**21 atoms
17.48 atoms
The atomic mass of copper is approximately 63.55 g/mol. Therefore, the mass of 9 atoms of copper would be 9 times the atomic mass, which is 9 * 63.55 g/mol. This equals 571.95 grams.
3.18 grams copper (1 mole Cu/63.55 grams)(6.022 X 10^23/1 mole Cu) = 3.01 X 10^22 atoms of copper there are 29 protons in one atom of copper, so............... 29 * 3.01 X 10^22 = 8.73 X 10^23 protons in 3.18 grams of copper
At 60°C, about 31.6 g of copper (II) sulfate will dissolve in 100 g of water. This means that about 3.4 g of copper (II) sulfate will not dissolve and will form a saturated solution.
63.54 g/mol
6.022*10**23 atoms / mol = avagadro's constant 63.546 g / mol = atomic weight of copper 1 atom / 6.022*10**23 atoms/mol * 63.546 g/mol = 1.05523082*10**-22g 1 g / 63.546 g/mol * 6.022*10**23 atoms/mol = 9.476599629*10**21 atoms
17.48 atoms
The atomic mass of copper is approximately 63.55 g/mol. Therefore, the mass of 9 atoms of copper would be 9 times the atomic mass, which is 9 * 63.55 g/mol. This equals 571.95 grams.
The product of the units atomic mass (g/mol), Avogadro's number(mol/atom), 1/density (m^3/kg) and, 1(kg/g) yield the volume of a copper atom. (63.5*(1/6.022E23)/(8930*1000)= 1.12E-23m^3. The volume of a sphere is given as 4(pi)(r^3)/3. Solving for r: r=(3*1.12E-23/(4pi))^(1/3)=1.41E-10m. Multiplying by 2, d = 2.42E-10m.
3.18 grams copper (1 mole Cu/63.55 grams)(6.022 X 10^23/1 mole Cu) = 3.01 X 10^22 atoms of copper there are 29 protons in one atom of copper, so............... 29 * 3.01 X 10^22 = 8.73 X 10^23 protons in 3.18 grams of copper
The density of copper is 10.0 g/mL. What is the volume in milliliters of a 2184-g ingot of copper?
1 mole of the element has 6.023 x 1023 atoms 1 mole = 4 g of helium = 7 g of lithium = 9 g of beryllium = 11 g of boron = 12 g of carbon = 14 g of nitrogen = 16 g of oxygen
One mole of oxigen (O2-the diatomic molecule) is needed for 127,092 g copper to form CuO.
At 60°C, about 31.6 g of copper (II) sulfate will dissolve in 100 g of water. This means that about 3.4 g of copper (II) sulfate will not dissolve and will form a saturated solution.
Cd= 24.23718445g
To find the number of moles of copper, we first need to calculate the total mass of copper in the sample. Copper has an atomic mass of 63.55 g/mol. The total mass of the sample is 1.20 g x 1024 atoms = 1228.8 g. Next, we convert this mass to moles by dividing by the atomic mass of copper: 1228.8 g / 63.55 g/mol = 19.36 moles of copper.