How many atoms are in 38.00 grams of fluorine gas?

Answer 1

Oh, dude, you're hitting me with some chemistry now! So, like, to figure this out, we need to know the molar mass of fluorine, which is 19.00 g/mol. Then, we can use Avogadro's number (6.022 x 10^23) to calculate that there are about 1.00 x 10^23 atoms in 38.00 grams of fluorine gas. But hey, who's counting, right?

Answer 2

To determine the number of atoms in 38.00 grams of fluorine gas, you first need to calculate the number of moles of fluorine gas using the molar mass of fluorine (19.00 g/mol). Divide the given mass by the molar mass to find the number of moles. Next, use Avogadro's number (6.022 x 10^23 atoms/mol) to convert moles to atoms. Therefore, there are approximately 3.01 x 10^23 atoms in 38.00 grams of fluorine gas.

Answer 3

The gram Atomic Mass of fluorine is 18.9984 and by definition consists of Avogadro's Number of atoms. Therefore, the specified mass of fluorine consists of (38.00/18.9984)(6.022 X 1023) or 1.205 X 1024 atoms, to the justified number of significant digits.

Answer 4

To calculate the number of atoms in 38.00 grams of fluorine gas, you need to convert grams to moles using the molar mass of fluorine (19.00 g/mol). Then, use Avogadro's number (6.022 x 10^23) to convert moles to atoms. The calculation is as follows: 38.00 g / 19.00 g/mol * 6.022 x 10^23 = approximately 1.20 x 10^24 atoms.