4.3 X Avogadro's number or 2.6 X 1024, to the justified number of significant digits.
4.39 grams carbon monoxide (1 mole CO/28.01 grams)(6.022 X 10^23/1 mole CO)
= 9.44 X 10^22 atoms of carbon monoxide
Quite a few!
4.37 X 1028 molecules of carbon dioxide (1 mole CO2/6.022 X 1023)(44.01 grams/1 mole CO2)
= 3.19 X 106 grams of carbon dioxide
============================!!
6.01*10^22 atoms
0.1mole
8
Is it 12
1 mole of CO2 has 1 mole of carbon atoms and 2 moles of oxygen atoms. So, 0.000831 mole of CO2 will have 0.000831 mole of carbon atoms.
The chemical formula of carbon dioxide is CO2; the molecule contain one carbon atom and two oxygen atoms.
1 mole of CO2 has 1 mole of carbon atoms and 2 moles of oxygen atoms.
6.022 x 1023
The formula is CO2, so there is one atom of carbon and two atoms of oxygen in each molecule.So there are 2.5x10^21 atoms of carbon in that many molecules of CO2.
2 atoms
Three atoms. Carbon dioxide is CO2
one
3
1 mole of CO2 has 1 mole of carbon atoms and 2 moles of oxygen atoms. So, 0.000831 mole of CO2 will have 0.000831 mole of carbon atoms.
there are 3 in tottal
The chemical formula of carbon dioxide is CO2; the molecule contain one carbon atom and two oxygen atoms.
After figuring out the calculations using the weight of CO2 and Avogadro's number, the total number of atoms in 110 grams of CO2 is 2.34 X 10^18 in sum.
12
1 mole of CO2 has 1 mole of carbon atoms and 2 moles of oxygen atoms.
6.022 x 1023
no. of atoms = no. of moles * avogadros no. no. of atoms = 6 * 6*1023 no. of atoms = 3.6*1024 (ans)