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How many atoms are in 4.39g of CO2?

Updated: 8/11/2023
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βˆ™ 11y ago

Best Answer

4.3 X Avogadro's number or 2.6 X 1024, to the justified number of significant digits.

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βˆ™ 13y ago
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βˆ™ 13y ago

4.39 grams carbon monoxide (1 mole CO/28.01 grams)(6.022 X 10^23/1 mole CO)

= 9.44 X 10^22 atoms of carbon monoxide

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βˆ™ 11y ago

Quite a few!

4.37 X 1028 molecules of carbon dioxide (1 mole CO2/6.022 X 1023)(44.01 grams/1 mole CO2)

= 3.19 X 106 grams of carbon dioxide

============================!!

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βˆ™ 11y ago

6.01*10^22 atoms

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βˆ™ 13y ago

0.1mole

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βˆ™ 11y ago

8

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Gabe Serna

Lvl 2
βˆ™ 3y ago

Is it 12

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Q: How many atoms are in 4.39g of CO2?
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