A mole of any substance has 6.022 x 1023 particles(atoms, molecules or ions) of that substance.
So 5 moles of chromium would have
6.022 x 1023 x 5 atoms = 30.11 x 1023 atoms.
To find the empirical formula, we need to determine the ratio of atoms present in the compound. First, convert the masses of chromium and oxygen to moles. The mole ratio will be approximately 2:3, indicating the compound is most likely chromium(III) oxide with the empirical formula Cr2O3.
6g hydrogen would be required for 160g ferric oxide in this reaction. The relative atomic weights of the elements are: Hydrogen - 1 Oxygen - 16 Iron - 56 giving the relative atomic weights of the compounds (on the left of the equation): Fe2O3 = 56×2 + 16×3 = 160 3H2 = 3×(1×2) = 6 So for every 160 units of mass of iron III oxide there will be 6 units of mass of hydrogen required. → for 160g of iron III oxide ÷ 160 × 6 = 6 g of hydrogen.
The formula of Chromium (II) oxide is CrO.
Chromium oxide is the light green inorganic compound coCr203. When dissolved in acid, it produces the hydrated chromium ions [Cr(H2O)6]3+.
Using the given masses, calculate the moles of each reactant. The limiting reactant will be the one that produces the least amount of product, which is copper. Convert the moles of copper to moles of copper (II) oxide using the balanced chemical equation. Then, convert the moles of copper (II) oxide to grams to find the mass produced.
Yes, Cr2O3 (chromium(III) oxide) is an inorganic compound. It is a metal oxide composed of chromium and oxygen, and it does not contain carbon-hydrogen bonds typically found in organic compounds.
To find the empirical formula, we need to determine the ratio of atoms present in the compound. First, convert the masses of chromium and oxygen to moles. The mole ratio will be approximately 2:3, indicating the compound is most likely chromium(III) oxide with the empirical formula Cr2O3.
To determine the amount of chromium (III) oxide (Cr2O3) needed to produce 421 g of chromium (III) sulfide (Cr2S3), you need to consider the molar ratio of the reactants. The molar mass of Cr2S3 is 256.16 g/mol, and Cr2O3 has a molar mass of 151.99 g/mol. First, calculate the moles of Cr2S3 produced from 421 g. Then, use the molar ratio from the balanced chemical equation to find the moles of Cr2O3 needed, and convert this to grams.
chromium oxide
6g hydrogen would be required for 160g ferric oxide in this reaction. The relative atomic weights of the elements are: Hydrogen - 1 Oxygen - 16 Iron - 56 giving the relative atomic weights of the compounds (on the left of the equation): Fe2O3 = 56×2 + 16×3 = 160 3H2 = 3×(1×2) = 6 So for every 160 units of mass of iron III oxide there will be 6 units of mass of hydrogen required. → for 160g of iron III oxide ÷ 160 × 6 = 6 g of hydrogen.
The compound Cr2O3 is chromium(III) oxide. It is a naturally inorganic occurring compound and it is used primarily as green pigment.
The formula of Chromium (II) oxide is CrO.
Ruby is composed primarily of aluminum oxide (Al2O3) with trace amounts of chromium oxide (Cr2O3). The chromium impurities within the aluminum oxide lattice are responsible for the vibrant red color of ruby.
Cr2O3 is, Chromium (III) oxide or simply Chromium oxide.
Chromium oxide may refer to:Chromium(II) oxide, CrOChromium(III) oxide, Cr2O3Chromium dioxide (chromium(IV) oxide), CrO2Chromium trioxide (chromium(VI) oxide), CrO3
Chromium oxide is the light green inorganic compound coCr203. When dissolved in acid, it produces the hydrated chromium ions [Cr(H2O)6]3+.
Using the given masses, calculate the moles of each reactant. The limiting reactant will be the one that produces the least amount of product, which is copper. Convert the moles of copper to moles of copper (II) oxide using the balanced chemical equation. Then, convert the moles of copper (II) oxide to grams to find the mass produced.