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14..4 elements of carbon,10 of hydrogen

2nd Answer:

Good grief!

There are 2 elements in C4H10: Carbon and Hydrogen.

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Related Questions

How many hydrogen atoms are in a molecule of butane?

4


How many double bonds are in the structural formula for butane C4H10?

There are no double bonds in the structural formula for butane (C4H10). Butane is a straight-chain alkane with four carbon atoms bonded to each other with single bonds and the remaining hydrogen atoms.


How many carbon atoms are in one mole of butane?

avogadro numbers of atoms


How many carbon atoms are in 2.00g of butane?

To find the number of carbon atoms in 2.00g of butane (C4H10), you first need to calculate the number of moles of butane using its molar mass (58.12 g/mol). Then, use Avogadro's number (6.022 × 10^23) to convert moles to atoms. Butane has 10 carbon atoms, so multiply the number of moles by 10 to find the number of carbon atoms.


How many hydrogen atoms are present in isobutane?

Butane means the molecule has 4 carbon atoms. Iso means one of those carbons is a side chain. The resulting molecule is something with a tetraeder shape, a carbon atom at the center with one hydrogen side "chain" and three CH3 side chains. (remember a carbon can make a total of 4 bonds. The formula for isobutane is therefore CH(CH3)3 or C4H10 for a grand total of 10 hydrogen atoms.


How many different structures have the formula C4H10?

There are two different structures possible for the formula C4H10: n-butane and isobutane.


What represents C4H10?

Many organic compounds have this chemical formula; see the link below.


How many moles of co2 form when 58.0 g of butane c4h10 burn oxygen?

4 moles


How many moles of carbon dioxide (CO2) are produced when reacting 6.00 moles of butane (C4H10) in excess oxygen (O2)?

19,5 g butane are needed.


How many moles of CO2 form when 58 grams of butane C4H10 burn in oxygen?

The answer is 3,99 moles of carbon dioxide.


How many moles of CO2 form when 58.0 g of butane C4H10 burn in oxygen?

For the combustion of butane C4H10, the balanced chemical equation is: 2C4H10 + 13O2 -> 8CO2 + 10H2O. First, calculate the moles of butane: 58.0 g / 58.12 g/mol = 1 mole. From the balanced equation, 2 moles of butane produce 8 moles of CO2, so 1 mole of butane will produce 4 moles of CO2.


How many carbon atoms are in a butane?

4