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How many butane molecules are in 6.02 x 10 -2 moles of butane C4H10?

To find the number of butane molecules in 6.02 x 10^-2 moles, you can use Avogadro's number, which is approximately 6.02 x 10^23 molecules per mole. Therefore, the number of butane molecules is 6.02 x 10^-2 moles × 6.02 x 10^23 molecules/mole = 3.62 x 10^22 molecules of butane.


How many hydrogen atoms are in a molecule of butane?

4


How many different structures have the formula C4H10?

There are two different structures possible for the formula C4H10: n-butane and isobutane.


How many double bonds are in the structural formula for butane C4H10?

There are no double bonds in the structural formula for butane (C4H10). Butane is a straight-chain alkane with four carbon atoms bonded to each other with single bonds and the remaining hydrogen atoms.


How many molecules are there in 11.7 grams of C4H10?

1 mole C4H10 = 58.1222g = 6.022 x 1023 molecules 11.7g C4H10 x 6.022 x 1023 molecules/58.1222g = 1.21 x 1023 molecules C4H10


How many carbon atoms are in 2.00g of butane?

To find the number of carbon atoms in 2.00g of butane (C4H10), you first need to calculate the number of moles of butane using its molar mass (58.12 g/mol). Then, use Avogadro's number (6.022 × 10^23) to convert moles to atoms. Butane has 10 carbon atoms, so multiply the number of moles by 10 to find the number of carbon atoms.


How many moles of co2 form when 58.0 g of butane c4h10 burn oxygen?

4 moles


How many carbon atoms are in one mole of butane?

avogadro numbers of atoms


How many moles of carbon dioxide (CO2) are produced when reacting 6.00 moles of butane (C4H10) in excess oxygen (O2)?

19,5 g butane are needed.


What represents C4H10?

Many organic compounds have this chemical formula; see the link below.


How many moles of CO2 form when 58 grams of butane C4H10 burn in oxygen?

The answer is 3,99 moles of carbon dioxide.


How many moles of CO2 form when 58.0 g of butane C4H10 burn in oxygen?

For the combustion of butane C4H10, the balanced chemical equation is: 2C4H10 + 13O2 -> 8CO2 + 10H2O. First, calculate the moles of butane: 58.0 g / 58.12 g/mol = 1 mole. From the balanced equation, 2 moles of butane produce 8 moles of CO2, so 1 mole of butane will produce 4 moles of CO2.