answersLogoWhite

0

I will use this formula, the convert.

q( in Joules ) = mass * specific heat Au * change in temp.

q = nCT

q = (150 grams)(0.129 J/gC)(175 C - 25 C)

= 2902.5 Joules

Now, 1 calorie = 4.184 Joules

2902.5 Joules (1 calorie/4.184 Joules)

694 calories required

User Avatar

Wiki User

14y ago

What else can I help you with?

Related Questions

If a 1.0-g sample of steam at 100 degrees Celsius loses 560 calories of heat what would the resulting temperature of the steam sample be?

80


How many calories are required to raise the temperature of a 35.0g sample of iron from 25 C to 35 C?

38 cal


how many calories are required to increase the temperature of a 27.3 g copper sample from 36.2 degrees C to 74.4 degrees C?

80 calories per gram


Why would water in a 100cm3 and water a 10cm3 cylinder measure the same temperature?

Because they are the same temperature. There are more calories of heat in a 100-ml sample of water that's at a certain temperature than there are in a 10-ml sample that's the same temperature...but 20-degree-Celsius water is 20-degree-Celsius water whether you have a thimbleful, a glassful or a swimming pool full.


When the temperature of a sample of water is negative 5 degrees Celsius the water is?

When the temperature of a sample of water is -5 degrees Celsius, the water is frozen and in a solid state.


If a sample is heated and rises in temperature by 12 degree celsius what is this temperature difference in kelvin?

The temperature difference in Kelvin is the same as in Celsius. So, if the sample rises by 12 degrees Celsius, it also rises by 12 Kelvin.


How much eat in calories is required to heat a 43 g sample of aluminum from 72 F to 145F?

How much heat (in calories) is required to heat a 43 g sample of aluminum from 72 F to 145F


How many calories are required to increase the temperature of a 27.3 g sample of copper from 36.2 degrees Celsius to 74.4 degrees Celsius?

I will work in Joules, then convert to calories.q(Joules) = mass * specific heat * change in temperature Cq = (27.3 g Cu)(0.385 J/gC)(74.4o C - 36.2o C)= 402 Joules (1 calorie/4.184 Joules)= 96.1 calories===========


A scientist measures the temperature of a sample of hydrochloric acid to be 85 celsius what is its temperature in kelvin?

85 + 273 = 358 K.


How much ice water will it take to cool the sample to 20 degrees celsius?

To calculate the amount of ice water needed to cool the sample to 20 degrees Celsius, you would need the initial temperature of the sample, the mass of the sample, and the specific heat capacities of water and ice. With this information, you could use the equation q = m * c * ΔT to determine the quantity of ice water needed to cool the sample.


) The temperature of a sample of water changes from 10 and degC to 20 and degC when the water absorbs 100 calories of heat. What is the mass of the sample?

one calorie of heat is able to raise one gram of water one degree Celsius so 400 calories could raise 1g of water 400 degrees, so it would raise the 80g by(400/80) 5 degrees Celsius plus the initial temp of 10 degrees, the 80g of water would have a final temp of 15 degrees Celsius


The vapor pressure of a sample of boiling water is 380 torr The temperature of the water is?

The temperature of the water is 100 degrees celsius.