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The cation of sodium has 11 protons and 10 electrons.

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How many protons and electrons dose Na plus have?

11 protons and 10 electrons


Difference between Na and Na plus?

Na+ will be a sodium atom that has lost an electron. Normally in atoms the amount of protons and electrons are equal, when you see a plus or minus charge on an atom its due to the loss or gain of electrons.


How many protons do Na plus have?

Any neutral atom or ion of sodium always has 11 protons in its nucleus.


How many protons and neutrons and electrons does the ion Na 1?

The ion Na+ has 11 protons, 12 neutrons, and 10 electrons. This is because sodium has an atomic number of 11, meaning it naturally has 11 protons and 11 electrons, but as an ion with a +1 charge, it has lost 1 electron.


How many protons electrons and valence electrons does na have?

Sodium's atomic number is 11. To be neutral then, it must have 11 protons and 11 electrons. Since sodium is in group 1, it has 1 valence electron.


How many electrons are in a sodium cation Na plus?

The number of electrons is 10.


What are the number of protons electrons and neutrons has Sodium?

Na has 11 protons and 12 neutrons and 11 electrons.


What is the symbol for sodium with 11 protons and 10 electrons?

The symbol for sodium with 11 protons and 10 electrons is Na+. The plus sign indicates that the sodium atom has lost one electron, resulting in a positive charge.


What happens to the number or protons as a Na atom becimes a Na plus ion?

The no. of Protons remains unchanged.


How many protons neutrons and electrons in Na?

Answer: 28 protons 28 electrons; the number of neutrons depends on each isotope of Na and Cl considered.


How many electrons are in a sodium ion which has the symbol Na plus?

A sodium ion with the symbol Na+ has 10 electrons. Sodium normally has 11 electrons, but when it loses one electron to form a Na+ ion, it has 10 electrons.


How many protons electrons does sodium have?

The atomic number of sodium is 11 which means it has 11 protons and 11 electrons.