This appears to be the formula for the oxide ion. Since oxygen has 8 protons, and this ion has a 2- charge, it must have 10 electrons.
16, oxygen has an atomic number of 8 and there are two atoms in O2
16 (8 + 8)
10
The number of electrons is 9.
10
The electron configuration of oxygen is [He]2s22p4.
Oxygen tends to gain two electrons to complete its "octet", making it O2- with the electron configuration 1s22s22p6
O2 shares two electron pairs, giving both oxygen atoms 8 electrons on the outer shell (noble gas configuration).
The number of electrons is 9.
O2- ion has a total of 10 electrons.
45
10
10
The electron configuration of oxygen is [He]2s22p4.
An atom of oxygen has 8 electrons, an O2 Molecule would therefore have 15, I think.
In the half reaction where an oxygen molecule becomes into two oxide ions, it obtains 4 electrons from the oxidising substance.
o2
Oxygen tends to gain two electrons to complete its "octet", making it O2- with the electron configuration 1s22s22p6
O2 has two unpaired electrons. The O atom has two unpaired electrons.
O2 shares two electron pairs, giving both oxygen atoms 8 electrons on the outer shell (noble gas configuration).