The number of electrons in a shell is 2n2, where n=shell number. So for the first shell, there is a maximum of 2 electrons.
hydrogen has only one shell and since it has atomic number one, its net number of electrons is one. the first shell can hold maximum of 2 electrons due to the bohr bury formula. so the number of electrons in its first shell is 1. to fill it 1 electrons are required which can be gained from any metal.
Beryllium like every other element excluding hydrogen has 2 electrons in its first shell.
The first electron shell can hold up to 2 electrons, the second shell can hold up to 8 electrons, and the third shell can hold up to 18 electrons. Therefore, a total of 28 electrons are needed to fill the first three electron shells.
As Nitrogen (N) have atomic number 7, and electronic configuration is 2,5. therefore N required 3 elecrons to complete their outermost shell or orbital.
The first shell can have 2 electrons, the second shell has 8 electrons and the third shell has 8 electron also. No matter what, electron fill up the first shell and then move into the next shell and then the next one. To answer the question, the first shell would have 2 electron and then the second shell would have six.
hydrogen has only one shell and since it has atomic number one, its net number of electrons is one. the first shell can hold maximum of 2 electrons due to the bohr bury formula. so the number of electrons in its first shell is 1. to fill it 1 electrons are required which can be gained from any metal.
Beryllium like every other element excluding hydrogen has 2 electrons in its first shell.
16 electrons would fill up the first four shells in an atom: 2 electrons in the first shell, 8 electrons in the second shell, 4 electrons in the third shell, and 2 electrons in the fourth shell.
The first electron shell can hold up to 2 electrons, the second shell can hold up to 8 electrons, and the third shell can hold up to 18 electrons. Therefore, a total of 28 electrons are needed to fill the first three electron shells.
As Nitrogen (N) have atomic number 7, and electronic configuration is 2,5. therefore N required 3 elecrons to complete their outermost shell or orbital.
The first shell can have 2 electrons, the second shell has 8 electrons and the third shell has 8 electron also. No matter what, electron fill up the first shell and then move into the next shell and then the next one. To answer the question, the first shell would have 2 electron and then the second shell would have six.
Carbon has four valence electrons, so it will need four more electrons to fill its outer shell.
Sulfur has 6 electrons in its outer shell. Therefore, it needs 2 more electrons to fill its outer shell.
well the first shell can only contain 2 electrons then in the second shell and up you can have up to eight that is how it goes
Oxygen has two electron shells because it has eight electrons in total, with two in the first shell and six in the second shell. Atoms tend to fill their outermost electron shell to achieve stability, and oxygen does this by sharing electrons with other atoms or gaining electrons to fill its outer shell.
Carbon needs 4 electrons to fill up its outer shell. It has 4 valence electrons and can achieve a full octet by gaining 4 more electrons.
Carbon has four valence electrons, so it will need four more electrons to fill its outer shell.