All p orbitals are the same - px, py, pz - 2 electrons in each, 6 in a p orbital in total.
2
There are no unpaired electrons in calcium, all 20 electrons are in pairs, i.e. each pair is configured in one orbital: 2x in 1s orbital 2x in 2s orbital 2x in each of the three 2p orbitals 2x in 3s orbital 2x in each of the three 3p orbitals and 2x in 4s orbital (these two are the valence electrons)
Iron has 8 valence electrons 6 from the 3d orbital and 2 from the 4s orbital.
4s electrons are lost first. The reason is because this is more energetically favored than losing d-electrons. As a result, all transition metals can bear a +2 charge. In many cases, d-orbital electrons can also be lost. Consider V+2 and V+3; the first has all of the d-orbital electrons (the 3 belonging to Vanadium) and has lost the 2 4s electrons. V+3 has lost the 2 4s electrons and 1 3d electron.
The 4s orbital falls in a slightly lower energy level than the 3d orbital when it is empty so it will fill with electrons first, but when it is full of electrons it rises to be above the 3d one so that it will lose electrons first as well.
There is merely one unpaired electron in Potassium. The electron configuration of potassium is [Ar]4s^1. This means that potassium has all the electrons of argon, plus one more in the 4s orbital. All the electrons of argon are paired, so the one electron in the 4s orbital is the only unpaired electron.
4
The electrons fill in the lowest energy orbital that is available. Electrons in the 4s orbital have a lower energy level than electrons in the 3p orbital, so the 4s orbitals are filled with electrons first.
1 in the 4s orbital, 19 electrons in all (K has an atomic number of 19)
because its energy level is lower
There are no unpaired electrons in calcium, all 20 electrons are in pairs, i.e. each pair is configured in one orbital: 2x in 1s orbital 2x in 2s orbital 2x in each of the three 2p orbitals 2x in 3s orbital 2x in each of the three 3p orbitals and 2x in 4s orbital (these two are the valence electrons)
Iron has 8 valence electrons 6 from the 3d orbital and 2 from the 4s orbital.
4s electrons are lost first. The reason is because this is more energetically favored than losing d-electrons. As a result, all transition metals can bear a +2 charge. In many cases, d-orbital electrons can also be lost. Consider V+2 and V+3; the first has all of the d-orbital electrons (the 3 belonging to Vanadium) and has lost the 2 4s electrons. V+3 has lost the 2 4s electrons and 1 3d electron.
The 4s orbital falls in a slightly lower energy level than the 3d orbital when it is empty so it will fill with electrons first, but when it is full of electrons it rises to be above the 3d one so that it will lose electrons first as well.
There is merely one unpaired electron in Potassium. The electron configuration of potassium is [Ar]4s^1. This means that potassium has all the electrons of argon, plus one more in the 4s orbital. All the electrons of argon are paired, so the one electron in the 4s orbital is the only unpaired electron.
The 3d sublevel is not filled until after the 4s sublevel, because the 3d sublevel has more energy than the 4s sublevel, and less energy than the 4p sublevel.
An orbital can only occupy maximum of 2 electrons. As p orbital consist of 3 orbitals. And has 3 orientations. Px, Py, Pz. So as there are 3 orbitals so p orbital can occupy at the maximum 6 electrons regardless of principle quantum no.. In 4p 4 is principle quantum no. So it represent 4p represent the p orbital of 4th shell. So it also occupy at the maximum of 6 electrons.
The lowest energy level of 4th electronic shell of an atom is '4s' it contains 2 electrons in maximum.